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Given 15 cot a=8 Find sin A and sec A | Trigonometry
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Exercise 8.1 class 10
Given 15 cot a = 8
Find sin A and sec A
Remember📋:
cot a = base/perpendicular
or
cot a = b/p
Base is the side adjacent to given angle
Perpendicular is the side opposite to given angle
Hint 💡:
Transpose 15 to RHS
cot a = 8/15
sin a = perpendicular/hypotenuse
sec a = hypotenuse / base
Practice:
In fig 8.13 find tan P - cot R
Revise✍🏻:
Quadratic Equation [2020]
#class10maths #trigonometry
Given 15 cot a = 8
Find sin A and sec A
Remember📋:
cot a = base/perpendicular
or
cot a = b/p
Base is the side adjacent to given angle
Perpendicular is the side opposite to given angle
Hint 💡:
Transpose 15 to RHS
cot a = 8/15
sin a = perpendicular/hypotenuse
sec a = hypotenuse / base
Practice:
In fig 8.13 find tan P - cot R
Revise✍🏻:
Quadratic Equation [2020]
#class10maths #trigonometry
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