Associativity and Precedence in CFGs

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Compiler Design: Associativity and Precedence in CFGs
Topics discussed:
1. Determining Associativity and Precedence from a given CFG.
2. Ambiguous Grammar to Unambiguous Grammar Conversion.

Music:
Axol x Alex Skrindo - You [NCS Release]

#CompilerDesignByNeso #CompilerDesign #AssociativityInCFGs #PrecedenceInCFGs

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Answer to the last problem is:
R -> R + R1 | R1
R1 -> R1.R2 | R2
R2 -> R2* | a | b | c

someone-lfeq

Hello sir, i learned lots of concepts regarding digital electronics and finally i placed at my dream company. So thanks a lot, keep doing this ❤️👍

gujjuavengers

Interactive presentations really help to stay focused and connected.

rajeshprajapati

Genuinely helpful in getting my homework done. Thanks!

devonbotney

Answer to H. W. Problem 08:59

R -> R + T | T
T -> T . S | S
S -> S* | a | b | c

Thanks Sir !

rajeshprajapati

Thank you Neso! At first I was confused why in Bison, the rules declared first have lower precedence than the rules declared later. This video cleared up that confusion for me. Thanks again!

yenzyhebron

Given the grammar (E-> E * F | F + E | F, F->F – F | id ) what are the precedence and associative rules of the operators in this grammar

niteshkumar-usjx

So for the boolean expression unambiguous grammar, how would you derive the parse-tree for the expression: NOT (T AND F OR T) ... ??? Anybody please help me out here!
I mean in the new unambiguous grammar, we can't apply not to an entire expression is this just the property of the grammar because there are no bracketting facility involved in it or something else?

samarthtandale

R -> R + R1 |R1
R1 -> R1 . R2 |R2
R2 -> R2 * | a | b | c

lemniscate

R--> R+R1|R1
R1-->R1.R2|R2
R2-->R2*|a|b|c
Can anybody confirm if my solution of the HW is correct?

shoykotrayhan

please complete Datastructures and discrete mathematics PPT'S ASAP

sivaranigade

Aniket/Sourav if you see this comment, reply on this thread.

_N_E_E_R_A_J_

R-> R+R1| R1
R1->R1.R2 | R2
R2-> R2*|a|b|c

shubhamkumarshaurya

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