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how to prove that det(adj(A))=(det(A))^n-1?
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We have square matrix A of order n x n. How can we prove that det(adj(A))=(det(A))^n-1 where det(A) is determinant of A and adj(A) is adjoint of matrix A.
how to prove that det(adj(A))=(det(A))^n-1?
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