Find the point(s) on the x-axis which is at a distance of √41 units from the point (8, -5).

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24. Find the point(s) on the x-axis which is at a distance of √41 units from the point (8, -5).
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Комментарии
Автор

Ohh ohhk sir...aapne baadme solve kr diya tha ...ohkk ...sorry 😅

NG_NIRAJ.
Автор

Sir, Jahan pe x² - 16x +89 - 41 = 0 hai usko solve krne pe niche -48 kaise aayega ( +89 - 48 ) = +48 hoga nah...kyunki ( + )× ( - )= ( - ) hota hai pr value toh bade number ki lagegi nah jo ki + 89 hai ...

NG_NIRAJ.
Автор

Sir galat hai
Aapka answer sahi hai but answer me +, - me aapka problem hai

sitaburnwal