1.10.1 Comparison of Functions #1

Comparing Complex Functions

Two functions can be compared by

1.Substitution
2. Applying Log

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[pradyumnsingh]

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[heilaal-mogren]

Literally AMAZING. Calm, comfortable, tidy and step-by-step explanation and reaching the point in a short time! this is what a perfect teacher means 👍🏼 MANY THANKS!

[marvel]

The last two questions are of GATE and I was so frustrated as I could not solve it. I just searched how to compare functions asymptotically and sir your video came up. Such a perfect explanation. Sir thanks a lot.

[asishraz]

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[wirito]

I like how you left this blooper in 1:34 Lol

Thank you for these amazing videos. I am learning a lot :)

[indianitguru]

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[health.upgradedbyscience.]

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[sushantgupta]

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[nattaphumjampalee]

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[umairgillani]

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[vaibhavkumar]

rupees and paise great way of explaining

[shobhitkumarpatkar]

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[omerakcan]

The best instructor I have ever seen in my life

[devildemon]

Sir in the previous problem u have comapred 2logn and logn and said that 2logn is greater(they have just different coefficient) but not in the last question

[manhazehra]

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[sujalchoudhary]

6:55 rupees and paisa perfect explanation

[aadarshbishen]

dividing f(n) and g(n) and apply limit n -> ∞ will be more easy to estimate.

[hemantbhangale]

Excellent progression and crystal clear content. Thanks!

[sumandas]

Thank you, sir, for this amazing video

[shreyavinchankar]

Do we not ignore the coefficient for logarithmic terms as well?
Ex. 3logn > 2logn but 3n = 2n, why is it so?