A2 U5.01

[ignaciomolina]

Ignacio M. Period 1
1.When the "c" constant changes, I think it determines if the point will be higher in the graph or lower. I see it an an addition to the function, for example f(x)2^x+3, if we just had, for example 2^2 then than would be just 4 but we add 3
2.When the "a" constant changes, I think that's the main point of the function and determines if the function will be a negative or a positive with an addition of b & c

[m]

Mathew C. P, 1
A.i think that when the c changes the slope will either be steep or stay normal.
B.when the a changes I think that this will determine the side that it is on in the graph, and again determine if it is positive or negative slope.

[andrewramirez]

1. It increases shortly after time.
2. If you were to plug in negative values then the point would start left on the x axis and stay the same

[Onlywith_ry]

Ryan D. P1 As the "c" constant changes the function shifts from left to right or right to left while as the "a" constant changes the graph either gets steeper or shallower.

[gregorywoods]

Gregory Woods Per.1
1. The C constant changes the slope of the graph varying from steep to shallow.
2. The A constant changes the side of the slope whether it be positive or negative.

[cesarinzunza]

Cesar I. 1
#1. I think when the C constant changes, it determines the slope of the graph.
#2. The A constant changes and determines if it's either negative or positive I believe.

[raullopez]

Raul Lopez
Period 2

If you change "c" the graph will transfer up if it's positive or down if negative.

If you change "a" it will become steeper with a positive integer and wider with a negative integer.

[robertomiranda]

Roberto M period 4


1. C constant increases shorter. Which will slightly increase higher.

2. A constant will increase when a number is plug in.

[christiancervantes]

Christian Cervantes P.1
1. As c constant changes there will be a shift
2. A constant will be a bit more steep as it multiples making the problem double

[brianflores]

Brian F. Per.4
1) When "c" changes, the graph either goes higher or lower depending on where it was before.
2) When "a" changes, the graph either gets stepper or shallower.

[briandelgadillo]

Brian Delgadillo Per1

1. The C constant increases shorter. What I mean it that it increases higher slightly.

2. The A constant will increase by a lot when a number is plug in.

[tamirmartin]

Tamir Martin P. 2
1. I believe the c constant changes a small portion of the over all graph 
2. I believe the a constant changes the points becoming a positive or a negative. 
But I do not understand why when you have a negative exponent it becomes a positive, used in your ex. 2^-10

[cityracerstudio]

Alejandro.j.period 4

1. The c constant tells if the function is going up or going down the x axis

2. The a constant says that that's how high the peak can go for a function

[jonathanmarcelino]

Jonathan.M.4 

1) When A constant changes the graph changes direction.
2)When C constant changes then the graph is moved up/down depending on the the sign.

[isaiahtaylor]

#1. The c value effects how drastic the lone on the graph goes ...the slope

#2. The a constant depicts the placement on the graph concerning the x axis ...yet in this answer I'm not sure ... I just realized tht small detail

[albertoromero]

Alberto R. Per.1
1) When the c constant changes i think that it is what will determine where the point on the graph will go negative, positive, up or down.
2) When the a constant changes I believe that it will determine how big or high the points can get. 

[Deadmanwalkshere]

Johan Merino P.2
1. I think when the C constant changes it effects the shape of the graph meaning that it will determine if there is a steep slope or not
2. When A changes it would determines if the the points will be positive or negative? not so sure on what happens with A.

[Slimeyyhsi]

Ishmael Howard Per. 2
A. I believe that constant c will increase shortly after time.
B. I believe that constant A would be a steeper graph because instead of adding or subtracting, it is multiplying which is bigger values.

Is there a point where the negative integers are colliding with the x axis?

[isaiahtaylor]

I also like were ishmeals approach on his second answer

[hectorcabrales]

Hector.C.Period 4
I would've thought that by squaring by a negative number I would then make the solution an imaginary number. However, I do remember the process of placing a 1 over to make it positive. Wouldn't that change the position of the whole graph? I know for sure that it'll change along with whatever C is but the one over the problem kinda goes against what we've seen before.