Worked example: sequence convergence/divergence | Series | AP Calculus BC | Khan Academy

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How can we tell if a sequence converges or diverges? See Sal in action, determining the convergence/divergence of several sequences. Created by Sal Khan.

AP Calculus BC on Khan Academy: Learn AP Calculus BC - everything from AP Calculus AB plus a few extra goodies, such as Taylor series, to prepare you for the AP Test

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You guys just made my college life easier xD thank you !

Penguin

wish I could like this video more than once!

drakeredwind

make a video with more complex sequences :D. What if it contains logs, for example?

conflagration

in the first sequence i.e a sub n=(n^2+9n+8)/(n^2-10n), if n=10 then the denominator is going to be equal to 0 and thus the sequence should be diverging, but its not, any reason?

zukauddin

Hey Sal could we do the second derivative and first derivative test cuz if it does converge then there should be two extremum and minimum values

akashsunil

but in the first example the nominator and the dominator converge into infinity, infinity/infinity is undefined. Shouldn't it be divergent?

CrusaderDeusVult

How 1st one is not divergent, divergence test states that if lim =/ 0 series divergres, and also if we use r=1 series is divergent

Karnex

your voice is awesome !! I love your voice !! >0<

XxsaixX

Sir, what if the highest degree in numerator is less than the denominamtor? Is it also converging?

jhn

But in the first problem the numerator will continue to have and additional 9n whereas the denominator will have a subtraction of 10n.. so as n tends to infinity.. inspite of both having n^2 the numerator will still grow more than the denominator so in that casr shouldn't it be diverging?? Anyone please help

srijatabagchi

then does that mean divergent is infinity?

kuochleaphea

I think you were wrong !! bcz: ( 1-1+1-1+1-1...=1/2)

xlogn

Worked example: sequence convergence/divergence | Series | AP Calculus BC | Khan Academy

Worked example: sequence convergence/divergence | Series | AP Calculus BC | Khan Academy

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