Solve this IF-THEN Problem in 1 Minute | NO Calculators!

preview_player
Показать описание

If a = 2021 & b = 1202, Then (a + b)(a^2 + ab + b^2)/(a^3 - b^3) = ?
Рекомендации по теме
Комментарии
Автор

Great job! The problem looks intimidating, but you made it simple!

iZAPMath
Автор

seeing premath channel fron india, state andhra pradesh

mokshithreddy
Автор

Answer 3223/819
Since a^3-b^3= (a-b)(a^2 +ab+b^2) (difference of cubes)
then (a+b)(a^2 +ab + b^2)/(a-b)(a^2 +ab +b^2)
then (a+b)/a-b)= or 3223/819
2021 +1202 = 3223
2021-1202 = 819
Answer= 3223/819

devondevon
Автор

a³-b³ = (a-b)(a²+ab+b²)

(a+b)(a²+ab+b²)/(a³-b³) = (a+b)/(a-b) = (2021+1202)/(2021-1202) = 3223/819 = 3.935

VolkGreg
Автор

And it is very very easy question.( I have solved it without doing it and I have needed 20 seconds).

mustafizrahman
Автор

I have solved it in 20 sce. [a+b/ a-b ]
Thanks

govindashit
Автор

Put questions based on Fibonacci numbers and limits, geometry

dennisphilip
Автор

I have solved it only 20 seconds. The answer of your question is 3223/819

mustafizrahman
Автор

I have solved it only 15 seconds. The answer of your question is 3223/819

mokshithreddy