Modeling annual temperature variation with trigonometry | Trigonometry | Khan Academy

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20=7.5cos((2pi/365)D)+21.5
20-21.5=7.5cos((2pi/365)D)
1.5/7.5=7.5cos((2pi/365)D)
arccos or cos^-1(1.772154)= 2pi/365 xD
D=102.94 but since it's in spring you subtract 102.94902 from 365 and you get about 262.05 days.
I used a graphing calc to check my work too.

thatnativeking
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I never thought that a math question can have a cultural difference, we have 6 different seasons here, so the thought of a cosine functions didn't even cross my mind.

It is just fascinating on so many levels.

SwapnilJha
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how can I calculate annual oscillation and semiannual oscillation at a given temperature data?

tsehayenegash
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The modeling graph can represent either a sine or cosine graph or are there things to look out for before one could say it's a sine or cosine graph?

omnibrain
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What is the name of this illustrating program :)?

TheZarownyDude
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I think you forgot that your maximum should be on the 7th of january

TIMSO