Related rates (Lecture Part 2) Point Moving Along Curve, y = cos x

[roylope]

Royce Lopez
MAC 2311
"The slope is stepper as we move past pi/4." (Hearn, 1:55)

[rileyfreemang]

Eric Haynes
MAC 2311
"the rate of change of y and the rate of change of x remember these are two variable related the change in them is not necessary the same pace" (Hearn 0:40-0:54)

[mstriker]

Mitchell Thanath
MAC 2311 2pm-3:15 M-R
"dx/dt is the rate at which we're moving horizontally and dy/dt is the rate at which we're moving vertically."

[usmcdd]

Rocky Rosado
MAC2311
"we need an equation equation that relates dy DT to DX DT how do we find that we need to have what equation so we're going to take the derivative with respect to t of both sides of the function yes we do very good so we're going to have dy DT equals negative sineX DX DT" (Hearn 2:10-2:32)

[Learn--Code]

Michael Samuels
MAC 2311

Thank you Professor Hearn,
So to be clear, in this particular video we refer to delta y as dy/dt and delta x as dx/dt?

[maxwelljakus]

Maxwell Jakus MAC2311 T/R 11:00 am - 1:15 pm
A part of this video I found helpful was the visual which allows visual learners like myself to see the point moving across the graph.

[vsim]

Vivica Simmons
MAC 2311 M-R
"so we're going to have dy/dt equals -sin(x) dx/dt

[anthonym]

1) Anthony M.
2) MAC1311 21Z
3). "How do we expect the rate to compare? Steeper in the negative direction"

[stephaniagrauer]

Stephania Grauer
MAC2311
A part of the video I found helpful was seeing how dy/dt relates to dx/dt and how we can use this information to solve problems. This will help me on the final.

[justin_credible]

Justin Quarless
MAC2311
A part of this video I found helpful was the graph showing the values we are concerned of. It helped me visualize dy/dt becoming smaller on the interval from [0, π/2].

[thethe]

Johnathan Spaulding
MAC 2311 M-R
"the slope is steeper as we move past pi over 4"

[alexandermarcelo]

alexander espinosa
MAC2311
it is important to find a formula that relates dy/dt to dx/dt

[shaneadelakun]

Shane Adelakun
MAC 2311
"DX DT is the rate at which we're moving horiontally and DY DT is the rate at which we're moving vertically"

[MyGamer]

Fathin Hossain
MAC2311, M-R 2pm
"dx/dt is the rate at which we're moving horizontally, and dy/dt is the rate at which we're moving vertically."

[omaritani]

Omar Itani
MAC2311
A part of this video that I found to be helpful was when you showed the graph of y=cosx it helped put things into perspective.

[mohammadabid]

Mohammad Abid
MAC2311 M-R
"So in the context of thinking of a point moving along a graph over time, y changes more in the second part which would indicate that y is moving a bit faster."

[paulchavez]

Paul Chavez
MAC 2311 2pm-3:15pm m-r
"to find the equation we need to find the derivative with respect to T to each side of each function "

[rushopolis]

Shamar Rush
MAC2311(11am TR)
"dx/dt is the rate at which we're moving horizontally, and dy/dt is the rate at which we're moving vertically." You know when you put it into words it starts making sense. lol

[juantomasini]

Mac2311
“The rates of change of Y and the rate of change of X are two variables. These two variables that while they are related the change in them is not necessarily at the same pace”