Mechanical Engineering: Particle Equilibrium (6 of 19) Worker Pulling on Mass Hanging from Crane

In this video I will calculate the force needed for a worker to pull a 10,000N mass hanging from a crane.

Next video in the Particle Equilibrium series can be seen at:

[aliensoup]

Isn't the force of the crane in y (Fcy) = 10, 000N? Thats the crane's force on the weight at equlibrium counter-acting the force of gravity. In this coordinate system that would be the y component of the total force on the weight. I'm assuming 10000N is the force at rest with no other sideways forces. The man pulling on the weight is the force in x. Both x and y forces acting on the weight to deflect it 3º add up to a magnitude greater than 10000N. Isn't the tension on the cable greater when the man is pulling on it?
With Fcy = 10000N, the Total force on the deflected weight (FcT) = 10000N/cos(3) ≈ 10013.7N.  
The x component of the man's force on the weight Fcx = 10013.7N * sin(3) ≈ 524.1N
The total force applied by the man = 524.1N/cos(30) ≈ 605N

[danielcoombe]

Firstly, that is a good physics problem. I will need a weekend to do one of those problems. In addition, I think that this physics problem would be practical while doing crane work with shipping. Particularly when you have a ship loading on to an oil rig or on to a dock. You would want to get some sort of idea on how many people you need to pull the container around. Therefore, I think that it would be good fun and useful to do a few of these physics problems.

[miguelducasse]

How do you convert for example 60 degrees to feet? say the cranes boom is at 60 degrees and the boom is 42 feet in length....if I wanted to measure the distance of the boom tip back to the boom heel in feet ? the crane computer does it automatic....

[matthiasandersen]

Really awesome videos! but haven't you mislabeled Fc. Shouldn't Fc be labeled on the hypotenuse? Isn't Fc equal to the weight, w=mg by your labeling in the video?

[AG-cxug]

At 7:25 Why do we assume 0.866Fp 0.0523Fc = 0 and there's no reaction force like the previous video? Thank you so much for such clear videos sir!

[RogelioJaimes-bzrs]

Muchas Gracias Profesor. También se puede resolver de manera práctica con el Teorema de Lamy. Saludos desde Chorrillos Lima Perú

[g_shiesty]

See, I’m new to this and it seems very simple might go more in depth

[karimkhan]

this   is   excellent   --  i  am   addicted  to  u r   lectures

[shubhamkukreja]

Sir why did you take force of crane? Instead of tension? Is it the same?

[heinmt]

If weight is KG, then we need to convert to N?

[desykheruddindesy]

Tolong jelaskan dalam bahasa indonesia