Crack the Code of Complex Powers: Finding the Principal Value of (1+i)^(4i)

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Dive into the world of complex numbers and unlock the secret to calculating complex powers like (1+i)^(4i). This video breaks down the process step-by-step, using clear explanations and helpful visuals. Perfect for students, math enthusiasts, or anyone curious about complex numbers!
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ln(2^2.5) after simplification in the last step

tomsmith
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(1+i)^(4i) = ((1+i)^4)^i = (-4)^i = (i^2i)4^i = e^(-π).4^i = e^(-π).(cos ln(4) + i.sin ln(4)). A slightly cleaner form of your end result.

Now a puzzle…. What is i^(4i)?

Is it = (i^i)^4 = [e^(-π/2)]⁴^4 = 0.2078… ^4 = 0.016… ?

OR

(i^4)^i = 1^i = 1 ?

OR is it both?

Note: x^i = e^(i.lnx) = cos(lnx) + i. sin(lnx). Thus 1^i = 1

ianrobinson
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Please solve (1+i)^(2-i)
Principal value and general value

mr.unique
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how would u use the principal to go backwards?

LP-htir