Japanese l can you solve this exponential problem?? l Olympiad Math

preview_player
Показать описание
Hello my Wonderful family!

Trust you're doing fine 😊

If you like this video on how to solve this nice Math Problem, like and Subscribe to my channel for me exciting videos 💥

Math Olympiad, Algebra, Simplification, Germany Math Olympiad,Math problem-solving, Grade 8 Maths, Grade 9 Maths, Nice Square Root Simplification, Japanese Can you solve, Imo Class 7, Imo Olympiad Class 7, Advanced math concepts,Math competition,Waec, Find the Value of X,Math Olympiad strategies,Challenging Math problems, How to Differentiate, How to Integrate, Thailand junior math Olympiad Problem,
Calculus,Algebraic expressions,Mathematics education,mathmastertv

#matholympiad​ #algebra​#math​#simplification​ #Exponents​#vedicmath​#viralmathproblem​ #howto​#mathematics​#viral​ #mathematicslesson​#calculus​#mathmastertv
Рекомендации по теме
Комментарии
Автор

81*9^x-9^x=180, 9^x=9/4, x=log(9/4)/log9, test, OK,

prollysine
Автор

Why you log both sides, when you got 9^(x-1)=1/4? You can use exponent rule and get (9^x)* (9^-1) =1/4, so (9^x)*(1/9)=1/4. Then multiply both sides by 9 and get 9^x=9/4. Now you can use the definition of logarythm and get x=log 9 (9/4)=log 3 (3/2)

adamoksiuta
Автор

Curious why you don't just take log base nine of both sides? Is there an advantage to going through common log first and using the change of base formula?

lornacy
Автор

Vamos a sacar el número atómico que es el Calcio (Ca) que es el elemento de la fusión de protones que tiene una estrella en sus gases como materia de la formación de materiales químicos de ebullición.

9^⁽*⁺¹⁾ - 9^⁽*⁻¹⁾ = 20

p = 9^⁽*⁾

9.p - 9^⁽⁺¹⁾ . p = 20
9.9^⁽*⁾ - 1/9 . 9^⁽*⁾ = 20
81^⁽*⁾ - 1/9 . 9^⁽*⁾ = 20
80^⁽*⁾/9 . 9^⁽*⁾ = 20
9^⁽*⁾ = 20.9/80
9^⁽*⁾ = 9/4
x = ₉ 9/4
x = Log₃(3/2)

startrek