Maths Made Easy! Circle Theorem: Part 2 | O&U Learn

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Circle Theorems? You heard right. There are rules. Rules for circles that involve triangles, quadrilaterals and A LOT of angles. Crazy right?But like always, don't worry about it. We've got this. Enjoy learning and conquering Circle theorems!

Whether you're in the UK preparing for your GCSEs, or in the US getting ready for your SATs, FCAT's, HGYNZWQYXWIF's (or whatever they're calling the exams that you studying for) Have no fear! 'O&U Learn' is here! (that rhymed). Ok, in all seriousness watch the video and enjoy!

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Circle theorem: Part 1

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Come Say Hi!

[nanaadwoaquayson]

God richly bless you! Your videos are just amazing! Fantastic end message. Keep up the great work!

[abdiazizhassan]

please do variation next i have an exam soon
keep up the good work

[jorgeg.narvaez]

Great Awesome... sample problems. I figured out every problem it will be nice to see how you will do it. Thanks!!!

[allanmandong]

O and U learn please help me. I need to know why Theorem no. 7 letter C is 32.5 degrees? My answer is 64 degrees, and based on what you’ve taught to us once the opposite side it will always equals into 180 degrees which is 25+25= 50 .. 180-50= 130 degrees and divide it by 2 it will equal to 64 degrees. I’m really confused right now, please tell me if i’m mistaken. Thank you so much! Btw, i’ve learned so much about this channel! Thank you again!

[prod.by.essenns]

Thank you very much!! It was interesting and easy.

[ethanc]

I calculated 76 degrees for problem (d) on the Theorem #5.

[meenarani]

Why is the answer for[D] 116 degrees . Even my daughter [who finished her GCSEs] also says that the answer at the end was completely wrong. She said that it should of been 64 degrees
So please can you write how you got the answer. THANK YOU . Anyway.

[kazuyamishima]

Could you please show working out in future episodes please

[pcsamz]

I don't understand Theorem 5 question C somone help please. And thank u

[RISaKIb]

please solve circle theorem 6 no.c and cricle theorem no.c a