Find the six trigonometric functions when given sine and a constraint on cosine

👉 Learn how to evaluate the six trigonometric functions given some constraints. When given the value of one trigonometric function, we can use a right triangle with one of its legs on the x-axis and the other leg, perpendicular to the x-axis is drawn such that the reference angle is at the origin. The x-coordinate of the given point represents the adjacent of the reference angle while the y-coordinate represent the opposite of the reference angle. The hypothenuse is the line joining from the origin to the terminal side of the 'opposite' line.

Using the Pythagoras theorem, we can obtain any of the unknown sides of the right triangle. Having the opposite, the adjacent and the hypothenuse of the reference angle of the right triangle, we can then evaluate the other trigonometric functions accordingly within the given constraint.

Organized Videos:
✅ Evaluate the Trigonometric Functions With Triangles
✅ Evaluate Trig Functions Using Special Right Triangles
✅ Evaluate the Six Trig Functions Given Right Triangle
✅ Evaluate the Six Trig Functions Given Equations
✅ Evaluate Trig Functions from a point | Learn About
✅ Evaluate the six Trig Functions given a point
✅ Determine the Quadrant Given Constraints
✅ Evaluate the trigonometric function with constraint

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[emilyjerez]

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[brianmclogan]

your welcome, make sure you check out my playlists on trig, I have a lot of videos for you

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[brianmclogan]

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[brianmclogan]

yes the opposite side will be negative, because tangent is negative in quadrant 2 and 4 but since the adjacent side is positive 2 you will construct your triangle in the 4th quadrant.

[samiam]

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[brianmclogan]

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[brianmclogan]

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