Maths Circles part 7 (Numerical : chord length) CBSE class 9 Mathematics IX

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Maths Circles part 7 (Numerical : chord length) CBSE class 9 Mathematics IX
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examfear you did great...
i understood the
but small mistakes....
love you EF

devimahesh
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sir in circle numericals of 10.3 q 1 how did you get the equation and that 8

Slowedsongsking
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nice i understand a lot but can i ask doubt if any

Slowedsongsking
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Guys, This is how 8x came :
3² - (4-x)²
now actually (4-x)² is in the form (4-x) (4-x)
So, 9 - (4-x) (4-x)
9 - 16(4x4=16) - 4x {4 x (-x)} - 4x {4 x (-x)} + x² { (-x) x (-x) }...we know that - - = + ...So that's y it became x² & not -x²
So it's now 9 - 16 - 4x - 4x + x²
9 - 16 -8x + x² { -8x came bcoz -4x -4x = -8x}
there was few mistakes in the video but that's alright
So now 25 - x² = 9 - 16 - 8x + x²
8x will go to the other side so it'll become positive.
8x = 25 + 16 - 9
8x = 32
x = 32 ÷ 8
x = 4...then watch the video

wildrose
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sir, thanks its rally helpfull for me

honeydaksh
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Sir in 2nd question we can see by construction that the common chord is passing through the center of the smaller circle so sir we can say that the length of common chord is 3cm

bhuvneshagg
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Sir good explanation but 2nd answer is a little complicated

vishalkrishnan
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Great work Mrs. Roshni and teachers!!!IM ur big fan and will; surely donate big amount when i grow and get a job!BUt can u juzt add history and civics history atleast!

shantanuthakur
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sir in numerical 3cm and 5cm with 2 common points the equation (4-x)^2 is 16+x^2-8x, but you have done 16-x^2+8x which is wrong

rohitmanimaran
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1:01.. can anyone also listen that scary background voice...what was that...😥

PreetiKumari-kwdq
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How to get study material from exam fear. com

prabavathiganesan
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dnt undrstnd prprly..roshni mam shud exaplain these

sugandhyshaju