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`((1+tan^2A)/(1+cot^2A))=((1-tanA)/(1-cotA))^2=tan^2A`

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Prove (1+tan^2 A)/(1+cot^2 A)=((1-tanA)/(1-cotA))^2=tan^2 A| Ex 8.4 Q5 (x)
`((1+tan^2A)/(1+cot^2A))=((1-tanA)/(1-cotA))^2=tan^2A`
1+Tan2A/1+Cot2A=(1-TanA/1-CotA)2=Tan2A
prove (1+tan^2 A/1+cot^2 A)=(1-tanA/1-cotA)^2=tan^2A ||class 10 exercise 8.4 Question 5 ka x part
(1 + tan^2 A / 1 + cot^2 A) = (1 - tanA / 1 - cotA)^2 = tan^2 A | Trigonometry | Ex. 8.4 | Class 10
class10,chapter8,ex-8.4,ques 5(x)| (1+tan^2A/1+cot^2A)=(1-tanA/1-cotA)^2=tan^2A
1+Tan2A/1+Cot2A=(1-tanA/1-cotA)2=Tan2A | Prove That 1+Tan2A/1+Cot2A=(1-tanA/1-cotA)2=Tan2A
1/(tan2A-tanA)-1/(cot2A-cotA)=cotA | trtrigonometry
10th.. (1+tan^2 A/1+cot^2 A)=(1-tanA/1-cotA)^2=tan^2A introduction to trigonometry EX. 8.4 Q.NO. 5
Prove that (1+tan^2A/1+cot^2A)=(1-tanA/1-cotA)^2=tan^2
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Prove: `(tanA)/((1+tan^2A)^2)+(cotA)/((1+cot^2A)^2)=sinAcosA`
1+tan²A / 1+cot²A = (1-tanA/1-cotA)² = tan²A
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(1+tan^2A)/(1+cot^2A)=[(1-tanA)/(1-cotA)]^2=tan^2A
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(1+tan^2A)/(1+cot^2A)=((1-tanA/1-cotA))^2=tan^2A solution explained in Kannada|PART5@Physics_Mestru
prove that `((1-tanA)/(1-cotA))^2=tan^2A`
Prove the following identity: (1 + tan^𝟐 A)/(1 + cot^𝟐 A)= (1 − tan A /1 − cot A)^𝟐 = tan^𝟐 A...
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