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Limit Laws - A tricky Question of finding limit using limit laws - Calculus
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In this video I will show you finding a limit using llimit laws, the question is a bit tricky.
Let f(x) and g(x) be defined for all x ≠ a over some open interval containing a. Assume that L and M are real numbers such that limx→af(x)=L and limx→ag(x)=M. Let c be a constant. Then, each of the following statements holds:
Sum law : limx→a(f(x)+g(x))=limx→af(x)+limx→ag(x) = L+M
Difference law : limx→a(f(x)−g(x))=limx→af(x)−limx→ag(x) = L−M
Constant multiple : limx→acf(x)=c⋅limx→af(x)=cL
Product law : limx→a(f(x)⋅g(x))=limx→af(x)⋅limx→ag(x) = LM
Quotient law : limx→a(f(x)/g(x))=limx→af(x)/limx→ag(x) = L/M when M≠0
Let f(x) and g(x) be defined for all x ≠ a over some open interval containing a. Assume that L and M are real numbers such that limx→af(x)=L and limx→ag(x)=M. Let c be a constant. Then, each of the following statements holds:
Sum law : limx→a(f(x)+g(x))=limx→af(x)+limx→ag(x) = L+M
Difference law : limx→a(f(x)−g(x))=limx→af(x)−limx→ag(x) = L−M
Constant multiple : limx→acf(x)=c⋅limx→af(x)=cL
Product law : limx→a(f(x)⋅g(x))=limx→af(x)⋅limx→ag(x) = LM
Quotient law : limx→a(f(x)/g(x))=limx→af(x)/limx→ag(x) = L/M when M≠0