Statistics Class 10 Maths One-Shot (Ch-14) | CBSE Class 10 Maths (Term-2) Crash Course | BYJU'S

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In this Episode of Class 10 One-Shot Series, we take up CBSE Class 10 Maths Chapter 14 - Statistics. We help you understand all concepts and topics related to Statistics and much more.

In this Term-2 Crash Course Series, we will discuss all the important concepts & topics of Statistics which help you to solve CBSE Important questions and get prepared for Class 10 Term-2 Board Exams.

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00:00 Statistics Class 10 Maths One-Shot
1:34 To understand the concepts
3:20 Q. Find the mean of the following data
5:14 Let’s have a look at the Scorecard
6:33 Grouping of data
8:57 Mean of Grouped data
10:08 Direct Method
11:12 Q. Find the mean runs scored by using that the direct method
14:40 Assumed Mean Method
15:43 Q. Find the mean runs scored by using that the assumed mean method
22:53 Order of Heights
23:22 Median - The middle most observation
27:04 Median - For grouped data
28:05 Median
29:31 Q. Find the median of the following Grouped data
35:41 Mode of grouped data
35:35 Mode
37:07 Q. Find the mode of marks of the candidates
40:13 Homework Question
41:08 Upcoming Session

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Mam plz stop this conversation whn u r teaching the concept... Plz🙂

ananyaray
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Byju's.... u r such a life saver!!! ur channel is the only one which teaches in english. thank u so much for your efforts

shijibiju
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Homework:
Here, the mode is 35.
So, the modal class = 30-40
Now, the lower limit of the modal class, l = 30
the frequency of the modal class, f1 = 16
the frequency of the class preceding the modal class, f0 = x
the frequency of the class succeeding the modal class, f2 = 12
the class size = 10
Applying the formula for mode. we get
l + [(f1 - f0)/(2f1 - f0 - f2)]*(h) = 35
30 + [(16 - x)/(2*16 - x - 12)]*(10) = 35
[(16 - x)/(32 - x - 12)]*(10) = 5
[(16 - x)/(20 - x)]*(10) = 5
(16 - x)*(10) = 100 - 5x
160 - 10x = 100 - 5x
-5x = -60
x = 12
Therefore, the missing frequency is 12.

Thank you ma'am for the wonderful session. 🥰🥰🥰

charvi
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ANSWER TO HOMEWORK QUESTION:
AS MODE IS 35, SO MODAL CLASS IS 30-40
L= 30, H= 10, f1= 16, f0=x, f2= 12
MODE = L+ [ f1-f0/2f1-f0-f2] * h = 35
30+ [16-x/20-x]*10 = 35
[16-x/20-x] * 10 = 5
16-x/20-x= 1/2
32-2x= 20-x
x= 12 is the missing frequency

bhagyavardhan
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Damn it's 2 AM

And at 10 AM I have my exam

ghoul
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Homework answer:
Modal class is 30-40 as mode is 35
Therefore:l-30, f1-16, f0-x, f2-12, h-10
Mode=l+f1-f0/2f1-f1-f2*h
35=30+16-x/2(16)-x-12*10

5/10=16-x/20-x
20-x=32-2x
x=12
Therefore, missing frequency is 12
Thank you ma'am for this amazing session. All my concepts are crystal clear now.

charviparkar
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In the case of byju's they focus on daily life examples and they just connect the things with our environment around us that's what we all need

jafrimujeeb
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U know litarally out of the 42 min of the video atleast 15-20 min will be conversation only

ammuandtinkuworld
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Homework Answer
X=12.
Ma'am today's session was fabulous🤗
Thanks a bunch, ma'am for
helping lots of students.💞💫😊😊

aditidutta
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I can see clearly
I don't have any future in engineering 🤩😂

Apan to commerce lenge....

MrBOI-xdcw
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Answer of Homework Question =
X = 12
Modal class
Mode = l + ( F1 - F0 / 2F1 - F0 - F2 ) ×h
35 = 30 +[ (16-x)/ 32 - x - 12 ] × 10
35-30 = (16 - x / 20 - x ) × 10
5 ( 20-x) = 160- 10 x
100 - 5x = 160 - 10x
X = 12

Hope you like my explanation

fenilsata
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Hello Mam I am Garima
Answer for yesterday's homework is x=12.

sumanprajapati
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Homework (Answer) :-
Missing frequency (x) = 12

prarthanar
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Mam ur explanation is too good I love it

aswithapotnuru
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Maam please stop the convo while ur teaching at the end u can discuss abt the chats it disturbs the class 😐

creative_pod_
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Homework Answers :-
Modal class will be 30 - 40 as 35 is the mode
fi = 16
f o = x
f2 = 12
l = 30
h = 10
Substituting all value in formula we get
35 = 30 + ( 16 - x / 32-x-12)10
5 = 160 - 10 x / 20 - x
100 - 5x = 160 - 10x
5x = 60
x = 12

nikeshmadavi
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Homework answer X=12, session was fabulous 👌🏻 💥💞💗💖❣🎉🌠💫 it helps a lot ❣

garimachoudhary
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Mam I have some questions for you can I ask🥰

dynamo-rznt
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Thank you so much mam, for this beautiful explanation

rameshwarkasotia
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12 is the ans of hw question.
Thankyou

shraddhagupta