Lecture 4 - To find m and n in gcd = 3587m + 1817n

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To find m and n in gcd = 3587m + 1817n by Prof. Pratul Gadagkar,  is licensed under a Creative Commons Attribution-NonCommercial-NoDerivatives 4.0 International License.
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find the solution of 621m+483n=k, where k is the gcd of 621 and 483, can you help me to answer this?

romelbuco
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Sir... please make video on topology atleast on basic concepts 🙏🙏

pravinyamgar