Proof: Triangle altitudes are concurrent (orthocenter) | Geometry | Khan Academy

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Showing that any triangle can be the medial triangle for some larger triangle. Using this to show that the altitudes of a triangle are concurrent (at the orthocenter).

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all the videos of khanacademy are a life saver

ashwinarora
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Beautiful, simple and elegant proof, thank you

bruceedward
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I would like to request the tutor to make a video on how to find and prove the orientation of vectors!

muhammadjavid
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Ok, now my question is why all the perpendicular bisectors are

xedgesharpz
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How is centroid of a triangle is equal to the orthocentre of medial triangle

tapaspal
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The new art history videos - will they be being embedded on the KA website soon?

hedonism
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i dont see how people dont WATCH THESE

Nitrodino
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Pls could u give the proof for concurrency of meadian s of triangle without using vectors

rajeshkumar-ecvj
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If two vectors A and B are non zero vectors and A=√2B then what is the orientation of these vectors means parallel, anti parallel, coplanar and concurrent? Can anybody explain?

muhammadjavid
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is there another way to prove that orthocenter is concurrent?

spiderjump