Vieta's Formula for Quadratics: Proof & Examples

[silviatotaro]

Thanks a lot for your videos. Happy new year from Italy!

[Chrisoikmath_]

Excellent!!
I know it; I learned it at school. Thanks for your great videos! I want to become mathematician like you. Happy new year!!!😀😀

[math]

thanks for sharing Vieta's formula for quadratics, very well explained, happy New Year

[wackojacko]

I have to recall how Intercept Form is derived...but I think what it means is when the function crosses the X axis...Vieta's formula is way cool.

[pranavamali]

how helpful it is
Thnx a lot premath

[moorthycisf]

i wanted to learn this in 8th standard you made this easy concept very very easy and also make hard concepts easy
thx also i subscribed

[johnryder]

Happy New Year Premath and Please God a good one viewing you great content

[zplusacademy]

Extremely beautiful ❤️ sir Happy New year 🙏🙏❤️❤️🙏🙏

[guyhoghton]

Note that:
α, β = [ (α + β) ± (α - β) ] / 2
∴ α, β = [ -b/a ± (α - β) ] / 2 ... ①
Also note that:
(α + β)² - (α - β)² = 4αβ ... ②
We can substitute from Vieta's formulae in ② to get:
b²/a² - (α - β)² = 4c/a
∴ (α - β)² = (b² - 4ac) / a²
⇒ ±(α - β) = [ √(b² - 4ac) ] / a ... ③
Now substitute for ±(α - β) from ③ into ① to get this handy little formula: ☺
α, β = [ -b ± √(b² - 4ac) ] / 2a

[theophonchana]

#factoring #factor #distributiveproperty #foil #foilmethod

[mahalakshmiganapathy]

wish you Happy and prosperous new year💗💗

[theophonchana]

#QuadraticEquation #trinomial #polynomial #binomial

[allahiseternall]

Someone just please pray for me that I live a happy perfect family life

[theophonchana]

b = -a (alpha + beta)
alpha + beta = -b ÷ a

[theophonchana]

c = alpha + beta
alpha × beta = c ÷ a

[piman]

This does not actually *solve* quadratic equations.