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If secθ = 17/8 , verify that 3 - 4 sin²θ /4cos²θ - 3 = 3 - tan²θ / 1 - 3tan²θ
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If secθ = 17/8 , verify that 3 - 4 sin²θ /4cos²θ - 3 = 3 - tan²θ / 1 - 3tan²θ
#skchazaribag
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Part 19) If sin θ =3/4, show that √cosec²θ -cot²θ/sec²θ - 1 = √7/3
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Part 21) If sin²θ + 3 cos²θ = 4 , show that tanθ = 1/ √3
Part 1)Introduction to Trigonometry
Part 2) 8.1 , q no. 1 NCERT
Part 3) ( k concept )
If sinA = 3/4 calculate cos A and tanA
In this video I have explained a question of Ex 10 of RS Aggarwal of Trigonometric Ratios class 10th
SUBJECT:Maths
Topic : Trigonometric Ratios
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For Further Information :-
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#skchazaribag
Previous video
Part 19) If sin θ =3/4, show that √cosec²θ -cot²θ/sec²θ - 1 = √7/3
Next Video
Part 21) If sin²θ + 3 cos²θ = 4 , show that tanθ = 1/ √3
Part 1)Introduction to Trigonometry
Part 2) 8.1 , q no. 1 NCERT
Part 3) ( k concept )
If sinA = 3/4 calculate cos A and tanA
In this video I have explained a question of Ex 10 of RS Aggarwal of Trigonometric Ratios class 10th
SUBJECT:Maths
Topic : Trigonometric Ratios
You Can Also Take Admission For Online Classes
For Further Information :-
7004022163(10:00AM-12:00PM)
Whats App:7004022163(Any Time)
If you like Our video then
Please like subscribe and share...
Thanking you... Have a great day...
0:05:42
16. If secθ=17/8, then prove that (3-4sin²θ)/(4cos²θ-3)= (3-4tan²θ)/(1-3tan²θ).
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If secθ = 17/8 , verify that 3 - 4 sin²θ /4cos²θ - 3 = 3 - tan²θ / 1 - 3tan²θ
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