Javascript Challenges - Longest Words

Javascript Challenges - Longest Words

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[bishalshah]

Using Map and filter



const longestWords = (str) => {
const maxLength = Math.max(...str.split(' ').map((el) => el.length));
return str.split(' ').filter((el) => el.length === maxLength);
};

[GodsDevilthF]

my solution when i tried the challenge

function longestWords(str) {
let words = str.split(' ');
let arrayLengths = words.map(e => e.length);
let maxLength = Math.max(...arrayLengths);
let longest = words.filter(e => e.length === maxLength);
return longest;
}

console.log(longestWords('i woke up early today'));
console.log(longestWords('i went straight to the beach'));

[lichesschess]

Love these series. I've followed a similar path and got the size of the longest word, but shortened up a little but when filtering and pushing it into the array:

function longestWords(str) {
let words = str.split(" ")
let size = 0;
let max = [""]
words.forEach((word) => {
if(word.length >= size)size = word.length})
max = words.filter(word => word.length === size)
return max
}

basically, after determining the longest size, i just pushed all the words whose length is equal to the size in to the array of max.

[leninsantiago]

function longestWords(str) {
let theLongest = [""];

str.split(" ").forEach((element) => {
if (element.length > theLongest[0].length) {
theLongest = [];
theLongest.push(element);
} else if (element.length == theLongest[0].length) {
theLongest.push(element);
}
});
return theLongest;
}

[bulatbaltin]

Thanks a lot! Great video! A suggestion to make a code more straightforward. Variable ‘size’ can be used as a length of previous max words, so there is no need to initialize max array with any value.
function longestWords(str) {
let words = str.split(' ');
let max = [];
let size = 0;

for (let i = 0; i < words.length; i++) {

let word = words[i];
if (word.length > size) {
size = word.length;
max = [word];
} else if (word.length === size) {
max = [...max, word];
}
}

return [...max];

}

[moulaoui]

const longestWords = (str) => {
const items = str.split(' ');
let longword = "";
items.map((item, index) => {
if(item.length > longword.length)
longword = item;
});
return items.filter(item => item.length === longword.length);
}

[noirsociety]

function longestWord(str) {
const words = str.split(' ');
const longest = Math.max(...words.map((word) => word.length));
return words.filter((word) => word.length === longest);
}

console.log(longestWord('I woke up early today')); // [ 'early', 'today' ]
console.log(longestWord('I went straight to the beach')); // [ 'straight' ]

[DEV_XO]

Very nice man, simple and clean explanation. Hope you keep uploading content like this, helps a lot to keep understanding / learning javascript.


Thanks!

[aboutthebook]

You are awesome! Hope you will upload Javascript challenges more than one in a day. Thank you.

[rasheds_miya]

This is awesome tutorials problematical

[alexotoous]

what does it take to know so much in JavaScript, How do I become good at coding pls. any guide ???

[B]

I think I did it with more simpler way. In your code, some points are unclear, as for instance why do we need size?

function longestWords(arr){
let x = arr.split(' ');
let longest = '';
let newArr = [];
for(let i=0; i<x.length; i++){
if(longest.length < x[i].length){
newArr = [];
longest = x[i];
newArr.push(longest)
} else if(longest.length === x[i].length){
longest = x[i]
newArr.push(longest)
}
}
return newArr;
}
my reason forthy doing the themes is to aware lorem help'))

[cjwebdev]

I am new at Javascript but the words "early" and "today" in the first sentence are the same length. Doe's Javascipt only show the first word in alphabetical order and then stops?

[gheorgheslicari]

Can be and better !!!! I did not like so much ! its hard to understand, its seem to be easy to understand how at the end he is explaining very bad ! He likes to confuse us .