UPSC CSE Prelims - CSAT 2023 Q.7) What is the remainder when...

[pksgkri]

We need not multiply the last digits even.there are 5x6 which ends with 0 at the end. Any no. multiplied will give 0 at the end . So even by observing we know last digits shall be zero. Options are not two digit nos. so the answer is the last digits is 0, option (a)

[Iambharatsangat]

Mene toh Bina solve kare hi iska sahi answer nikal liya

[AptitudeDestination]

Yes last two digits are the reminder, but the options have only one digit which means the remainder is a single digit that is the last digit. Since the last digit was found to be 0, we can conclude that the last two digits are 0.

[icarus]

Try the remainder of 35*18*31*15*17 by 100 it will show ass 00 acc to ur formula but actually its remiander is 50

[dostiBaniRaheBus]

so American also preparing for UPSC nowadays

[devashishsontakke]

Only we have to find how many 2/5 are there

[ayu]

ques 2nd need not to be solved with this much effort

[PrakharRSingh]

Why not just divide it until the denominator is 1.
If that's possible, we have the last digit as zero.

[Manish_by_-Upsc_study.]

Hum Hindi walo ko bhi jee lene do mam pura English hi ku

[kalidassg]

You said divisibility of 100 is depend on the last two digits(00). But later you find the last digit(0) and said the remainder is zero🤔. Please clarify it?

[mohanamuralikrishnajalaneela]

wanna talk to u mam on aptitude, , pls allow me

[VamsiUppuluri]

If we proceed to multiply the last digits we get 0, 5x5x5x5 is 625, where did we get 0?