Program to Check for Leap Year in Java by Deepak

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Program to Check Leap Year in C (HINDI/URDU),
Java walk through: Leap Year,
11 Find year is leap year or not in java,
Java Program for leap year,
Given year is leap year or not using if else in Java,
Concept of Leap Year,
How to check whether a given year is a leap year or not through a Java program ?.
Program for Leap Year in C (HINDI)
Program to Find Leap Year in C (HINDI)
Program to Check Whether Year is Leap Year or Not

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SmartProgramming
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Sir you have such a pure soul ... Your tutorials are very clear to understand.... In whole youtube channel you are the only one whose tutorials are easy to understand...
Thanku so much

SEMWALPRODUCTION
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this is by far the most usefull and friendly beginner java course available on youtube..
A good teacher is so so imp...
Thank you sir.

arindammahanty
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best channel to improove programming logics

yadavsushil
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Thank you so much sir ...maine bohot vedios dekhe baki chanels ke lekin aapke tarah easy way me kohi nhi padta sir , aap jo padhate ho bohot easily samj jata hai sir,
again thank you so much sir

sanketsirsikar
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Hi Deepak Sir, I would like to know the step/sequence in which compiler checks for the validity of the condition in multiple if-else block program. For this example of the leap year program every if-else block is checked separately or first of all, ifs are checked then followed by else blocks?

avinashkumar
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bahut achha session rahta hai sir apka,
glad i could find this in time of need 😊.

dhananjayrai
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Thks sir for this valuable information

a.k.gautam
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actually directly year%4==0 is enough for leap then why another logic

sangrampradhan
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but sir 2016 is not divisible by 400 the answer is giving 5.04 and you told that 400 should be proper divide

mohdraza
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Thanks u explain this program in best way

pranavjadhav
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hii
you are doing great work
very useful video...
thank you

pradipshelar
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sir, please make a video for advanced java, servlet JSP and collection framework.

rutvashukla
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Import.java.io.*;
Class P1
{
Public static void main()throwIOE.xception
{
Buffered reader=new input buffered reader (new input stream reader(system.in));
System.out.println("input a number");

Int k=a;
Int rev=0;
While(a<0)
{
Int n=a%10;
Int b=(n*10)+r;
Int a=a/10;
}
If(r==k)
{
System.out.println("no.is palidimone")
}
else
{
System.out.println("no is not palidimone")
}
}
}
Sir yes sahi ha ya nahi

songworld
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Nice sir. We can also use parameterized function.

srishhh_was_bored
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Nice videos but why don't you make in English.

mdhu