Graphing y = -2 cos(2x)

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I can now graph this types of problems confidently!
Thanks a lot!

sharonkadode

What you explained in 4:59 my professor has spent 2 weeks explaining and I finally understand now thanks to you.

vonh

The way you explain graphing is crystal clear! THANK YOU

angelyherrera

Patrick you are a perfect teacher for graph thank you for your help

ajaysarangam

Cramming for my Advanced functions exam tomorrow! Your video's help so much!!

alysadunkley

I almost forgot the lesson I've learned last Thursday, so this video plus another related vid. was seriously helpful! ^^

sanahita

Both u and Salman Khan from the Academy are the friends I never had! :( in other words both u are awesome!! :D

Dii

@bebekou14 it's divided into 4 intervals - 1/4 pi or pi/4, 1/2 pi or 2/4 pi or simply pi on 2, 3/4 pi or 3 pi on 4 and finally pi. in other words 1 quarter, 2 quarters (or 1 half), 3 quarters and 1 whole.... hope you understand

MrMcVilla

I alway forget cosine graphing. this video really helped me.thank you PatricJMT

fredy

this video really reinforced what i learned a while ago, thak you Mr. patricJMT

madra

This was so helpful. I finally understand. Thank you. ❤️❤️

dookledee

learned more in 5 minutes then in a week of class! Thanks!

martinzimmer

Thank you very much for the video you made. It is very much appreciated 🙏 ☺️

pewpewlasergun

Thank you so much, your videos are really helping me understand circular trig!

amanda

I have to tell you Thank u, thanks for the help that not even my teacher was able to do it. I am speechless .

SY-hnii

How do you find the x axis values? I'm really struggling with that.. or is that the parent functions axis?

zohaawan

that means that one cycle of the function lasts 4pie. That means from start to end of one cycle it is 720 degrees

ScandinavianFish

Awesome video. I hope in the future you have example that range in difficulty. Normally, I have a hard time applying this into functions which are more difficulty. Otherwise awesome! Love your vids

medocekic

so if the a value was 2 instead of -2, the cosine function would start at the point (0, 2) right? so is it right to assume that whenever you are asked to draw a cosine graph with no shift, the starting point has the same y value as the a value is ? (sry if i made it sound confusing..)

misty

can you explain how you started the graph at pie over 4 please

ttjay

Graphing y = -2 cos(2x)

Graphing y = -2 cos(2x)

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