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Diagonal BD of a parallelogram ABCD intersect the segments AE at F, E is on BC.Prove thatDFxEF=FBxFA
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Diagonal BD of a parallelogram ABCD intersect the segments AE at F, Where E is any point on the side BC. Prove that DFxEF=FBxFA.
CLASS 10
SIMILAR TRIANGLES
IMPORTANT PROBLEM
CBSE SYLLABUS
STATE SYLLABUS
TELANGANA AND ANDHRA PRADESH
KHAJA MOHAMMED
If you have any doubts you can ask me through WhatsApp (9848427242)
CLASS 10
SIMILAR TRIANGLES
IMPORTANT PROBLEM
CBSE SYLLABUS
STATE SYLLABUS
TELANGANA AND ANDHRA PRADESH
KHAJA MOHAMMED
If you have any doubts you can ask me through WhatsApp (9848427242)
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