Identifying the graphs of a function and its derivatives

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Identifying the graphs o the derivatives of functions may be a confusing concept for many calculus students. This video was made to remove that confusion.
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That's one of the BEST thumbnails I have ever seen!

Orillians
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Prime Newtons is a gold mine of information! 🎉😊

punditgi
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This one was easy, graphically guessing the slope at x=0 was a fast way to build the tree of possibilities and guess which were the respective derivatives. Thank you for the fun time

TheFlarMr
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Thanks for your hardwork teacher
I hope to be like u in future❤👌
Following you from Egypt

ammaryasser
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Great Video and explanation as always! Thnx for your hard work!
Greeting from Spain!

voidkfox
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Hi teacher, thx for your hardworking, i'm from Algeria i love maths, i will be highschool student next year(i'm 15, and will take my passing exam in 2 days, wich me good luck )
Have you done videos for 1st year highschool level
PS: sorry for my bad English, it's my 3rd language, when i watch your videos i try to understand what you are writing more than what you are respectively saying 😅

NJM-DZ
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Never stop watching Prime Newtons, because when you stop watching you stop learning.
❤️🙏

kragiharp
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Thanks sir it helps a lot you are really amazing. It's a request could you please also explain precalculus other than advanced

cool_dude
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The method I used to answer this question was to look at the x-intercepts of one graph and see if they share the same x-coordinates as the extrema of another graph. If so, then the former graph is very likely to be the derivative of the latter.

ryanwilson
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Please have you done anything on hyperbola

goodnesspascal
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Prime Newton, what is the f(x) of the original (RED) function? x^6 +

dirklutz
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Bro pls make a video on this problem. If a=7-4sqrt3, find sqrt a + 1/sqrt a

aneeshbro
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Any function's derivative will be zero if at that point, the tangent to the graph is parallel to x-axis.
Hence - Red graph = f(x)
Blue graph = f'(x) [Derivative]
Green graph = f"(x) [Second derivative]
Black graph = f'''(x) [Third derivative]
Just by justifying this simple fact you can answer this question withing seconds. This is competitive question after all so who is gonna solve the whole question ??😛😛

Pramit
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to be honest im confused on the derivatives graphs.. 😂 i rather go with the equations

childrenofkoris
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the third derivative got me confused asf

Malke