Integration (ax+b)^n - How to? | ExamSolutions

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Here you are shown how to integrate integrals of the form (ax+b)^n. Check out the contents below.

PAGE 1: Introduction and examples 0:00:04
Question to try 0:08:51

PAGE 2: Proof of the formula
The proof of the formula is demonstrated as the inverse of the chain rule 0:11:14

PAGE 3: Further practice
Questions to try 0:17:00

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Videos in this series:
INTEGRATION 1: What is Integration?
A look at basic indefinite integration
INTEGRATION 2: Definite Integration
Looks at definite integration and applications.
INTEGRATION 3: Area under a curve
Looks at areas under a curve to the x-axis, below the x-axis, between a curve and a line and between two curves.
INTEGRATION 4: Integrals of the form (ax+b)^n
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  1. ExamSolutions
  2. integral (ax b)^n
  3. integrate (ax b)^n
  4. integral (ax b)^n dx
  5. integral (ax b)^2
  6. integrate (ax b)^3
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Комментарии
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The best explanation I have ever had as to how differentiation and integration are connected.

st.ursulasprimaryschool
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i feel lucky to be able to just look up so great examples and explanations, great video

balintmucsanyi
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This type of video i was searching for the whole day. Great explanation

tesgatesfane
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Thanks ExamSolution! In this video - after some testing - I also learned that the integral of the binomial cube is not equal to the integral of the expansion of the binomial cube!

marcocenci
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Hi Exam Solutions you're videos are very helpful and amazing to watch
Could you make videos on very hard questions from each past paper and also could you make videos for the Solomon papers and if you have spare time could you also have a look at past papers made by Dr Madas
Once again I really appreciate your work and effort to make this videos and would be extremely grateful if you could make videos for really hard questions

razeboxanimations
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thanks for your videos, i dont understand that good english but your videos are really good even i can understand them

ElpatitoCuakHD
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Hi, so I've been given an exam-style question involving reverse chain rule and substitution, the integration of x+7/(2x-3)^1/2. How do I go about this and does it give me a result in the form ln modulus with the 2x-3 variable inside? Following the rules we have none seem to make any sense when the numerator has an expression such as x+7.

JFoxyYT
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at 8:39 do you have to change the ^5/3 into the cube root of (7x-2)^5 or does it not matter?

throwawaystowaway
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Sir but in 4÷(9x-5)^2. In the textbook they did using the ln format.

mdsayed
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I find this is NOT a very helpful method. I have a bit of an issue with the term 'reverse chain rule', but the process that 'reverse chain rule' advocates is FAR more useful & memorable than remembering YET ANOTHER formula that you're advocating here. The method you show invariably leads to confused students because they confuse and/or misremember the fraction in the formula you show here.

TheBegbiesan
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