Double Integration Method Example 2 (1/2) - Mechanics of Materials

preview_player
Показать описание
This is a double integration method example problem for a simply supported beam with linear and uniform distributed loads. This video shows how to calculate slope and displacement functions and then determine the maximum displacement of the beam.

Part 1: Calculating Reactions, Moment Functions, and Antiderivatives

Part 2: Identifying boundary and continuity conditions, solving for constants, determining the maximum deflection of the beam
Рекомендации по теме
Комментарии
Автор

Man your "welcome back to structure free definitively killed me lmao

ahmattahar
Автор

Reviewing basics is always a pleasure. Thanks

ahmattahar
Автор

You have saved my final examination. Yeah~

waichingwong
Автор

Is it possible to look at section 2 from the left. starting at the 3m mark (change from linear to constant)? Im attempting that way and I get that M2 = -4x^2. However im missing the + 22. How can i account for that using the technique i described in the sentance above?

DrDerivative
Автор

Can we use singularity for this kind of question where the triangular distribution load ends at the center of the beam length?

johaneswijaya
Автор

thanks so so much for your perfectly clear, well paced, engaging vids. think I spotted in the expression for deflection with respect to x1,
should be -1/20 * x1^5 rather than -1/45 * x1^5

brookesmith
Автор

at time 4.22 x/3 should be 2x/3 ?.  The triangular load should act at a distance of 2x/3 or (x-x/3). ???

stevearnold