Calculus of Variations Shortest Distance in Polar Form

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[pablocastrejon]

Just note that integral of -dx/√(1-x^2) is equal to -arcsin(x)+c if you suppose c=pi/2 then you have -arcsin(x)+pi/2 which is equal to arccos(x)

[RossMcgowanMaths]

Thanks Pablo I will have a look at this !