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Tudor Hall Maths Algebra differentiation, equation of a tangent, turning points
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For each term, use the formula 'multiply by the power and subtract 1 from the power'.
The differential, dy over dx, gives a formula for the gradient anywhere on the curve. To find the gradient at any particular point on the curve, substitute the value of x into this formula.
To find the equation of the tangent to that point, use y equals mx plus c, with m equal to the gradient at that point. Then use the coordinates of the given point to find c.
At a turning point, the differential is equal to zero. dy over dx equals 0 Solve the equation to get the x coordinate and swap the value of x into the equation of the curve to get the y coordinate.
The differential, dy over dx, gives a formula for the gradient anywhere on the curve. To find the gradient at any particular point on the curve, substitute the value of x into this formula.
To find the equation of the tangent to that point, use y equals mx plus c, with m equal to the gradient at that point. Then use the coordinates of the given point to find c.
At a turning point, the differential is equal to zero. dy over dx equals 0 Solve the equation to get the x coordinate and swap the value of x into the equation of the curve to get the y coordinate.