Block Diagram Reduction (Solved Example 2)

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Control Systems: Block Diagram Reduction (Solved Example 2)
Topics discussed:
1. Splitting of a 3 input adder into two 2 input adders.
2. Solved Example based on the calculation of the overall transfer function of a Control system given in the form of Block Diagram Representation using Block Diagram Reduction rules.

Music:
Axol x Alex Skrindo - You [NCS Release]

#ControlSystemByNeso #ControlSystems #BlockDiagrams
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2nd Problem:

1) split the right-most adder into the rest of the block diagram + a negative feedback loop which can be solved as (G3/(1+H3G3))

2) move the branch from before G2 to after G2, and compensate with gain 1/G2. This puts two branches in parallel whose overall gain is (1+1/G2).

3) now the left hand side is two nested negative feedback loops. The inside feedback loop solves to G2/(1+H2G2). The outside then solves to G1G2/(1+H2G2+H1G1G2).

The total comes from multiplying the results from 1) 2) and 3) together.

gregoiredesclee
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Q1 -- (Block Reduction Method)
Q2 -- [G1.G3.(1+G2) /((1+G2H2+G1G2H1).(1+G3H3))] (Method 2)

imsouvikkarmakar
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The answer for the first homework problem__ numerator= G1G2G3 and denominator = 1 + H1G2G3 - H2G2G3 + H3G2G3

_tanishkgupta
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sir, your lectures are great, pls add the remaining ppts

shreyanshgupta
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Sir ur lecture is just Pls complete the syllabus quickly

keerthanasaravanan
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Thank you for the lecture. You have save my life!😂

itsagift
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great to see you again...please upload videos frequently...we have this in our current semister

raamatulasi
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sir in this example we have to determine the closed loop transfer function but you have calculated the open loop transfer function, please look into it.

piyalbhowmick
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I really appreciate U now can do any problem concerning block diagram algebra🎉

wanisamuel
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Sir, please reply if you are going to frequently updated the playlist, we need this course by the end of 4 months 🙏

sreerajguptays
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Thanks man, you saved my life, this adder with 3 input sucks! I couldn't find an explanation anywhere.

TheArrowster
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Ans
Ans
In second problem, shift the take-off point before the block G2 after it.Then simplify it.

Divyanshusrivastava
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gm sir. sir ur lecture is very understandable ...awesome teaching sir ..sir will u teach electrical measurements also sir?

deepikavarma
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You re incredibile, thanks to you i will get a Google mark

davidmusteata
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On Step 2 of this problem, will I be wrong to consider G1 and the positive feedback as a closed loop?

eulendabasetsana
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Q.1) Ans:- G1.G2.G3/G2.G3.H1 - G2.G3.H2 + G2.G3.H3
-OR-
=G1.G2.G3/G2.G3.(H1-H2+H3)

sameermeshram
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it seems the postive feedback u have taken is wrong it will be G1/1-G1 the final answer look like correct me if iam wrong

akshaysagacious
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The answer came out to be

while using Mason Gain formula. Why is it different?

amandhakal
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The twist when he introduce the 11th rule😂😂😂

pranavvasoya
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Q2 ans- G1G3(1+G2) /((1+G2H2+G1G2H1) (1+G3H3))

Rising_sun_