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Evaluate the integral โซ๐พ ๐งฬ ๐๐ง where ๐ถ is the straight line from the point (1,0) to the point (1,1)
ะะพะบะฐะทะฐัั ะพะฟะธัะฐะฝะธะต
๐ช๐๐๐๐๐๐ ๐จ๐๐๐๐๐๐๐ ๐ป๐๐๐๐๐๐ ๐๐๐๐ ๐ช๐๐๐๐๐๐ ๐ฐ๐๐๐๐๐๐๐
๐ธ๐๐๐๐๐๐๐:-
Evaluate the integral โซ๐พ ๐งฬ ๐๐ง , where ๐ถ is the straight line from the point (1,0) to the point (1,1) .
๐บ๐๐๐๐๐๐๐:-
We know that ๐ง = ๐ฅ+๐๐ฆ
โด ๐๐ง=๐๐ฅ+๐๐๐ฆ โ๐๐ง=๐๐๐ฆ (โต๐ฅ=1โ๐๐ฅ=0)
and ๐งฬ = ๐ฅ - ๐๐ฆ
Here line ๐ด๐ต , ๐ฅ=1 and ๐ฆ moves 0 to 1 .
โซ๐พ ๐งฬ ๐๐ง = โซ แคฒ แท(1-๐๐ฆ)๐๐๐ฆ
โโซ๐พ ๐งฬ ๐๐ง = ๐โซ แคฒ แท(1-๐๐ฆ)๐๐ฆ
โโซ๐พ ๐งฬ ๐๐ง = ๐[ ๐ฆ] แคฒ แท+[ ๐ฆยฒ/2] แคฒแคฒแคฒ แท
โโซ๐พ ๐งฬ ๐๐ง = ๐[1-0] + [(1/2)-0]
โโซ๐พ ๐งฬ ๐๐ง = ๐+(1/2)
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Solved...!!!
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#complexanalysis #csirnet #complexintegration #riemannintegral
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๐ธ๐๐๐๐๐๐๐:-
Evaluate the integral โซ๐พ ๐งฬ ๐๐ง , where ๐ถ is the straight line from the point (1,0) to the point (1,1) .
๐บ๐๐๐๐๐๐๐:-
We know that ๐ง = ๐ฅ+๐๐ฆ
โด ๐๐ง=๐๐ฅ+๐๐๐ฆ โ๐๐ง=๐๐๐ฆ (โต๐ฅ=1โ๐๐ฅ=0)
and ๐งฬ = ๐ฅ - ๐๐ฆ
Here line ๐ด๐ต , ๐ฅ=1 and ๐ฆ moves 0 to 1 .
โซ๐พ ๐งฬ ๐๐ง = โซ แคฒ แท(1-๐๐ฆ)๐๐๐ฆ
โโซ๐พ ๐งฬ ๐๐ง = ๐โซ แคฒ แท(1-๐๐ฆ)๐๐ฆ
โโซ๐พ ๐งฬ ๐๐ง = ๐[ ๐ฆ] แคฒ แท+[ ๐ฆยฒ/2] แคฒแคฒแคฒ แท
โโซ๐พ ๐งฬ ๐๐ง = ๐[1-0] + [(1/2)-0]
โโซ๐พ ๐งฬ ๐๐ง = ๐+(1/2)
------------------------------------------------------------------
Solved...!!!
.
.
#complexanalysis #csirnet #complexintegration #riemannintegral
.
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