Calculus 2: Improper Integrals (4 of 16) Another Example

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In this video I will find the integral (from negative-infinity to 0) of xe^x.

Next video in the series can be seen at:
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sir there is - sign before t.e^t which will give -t/e^-t & final result should be 2

legendaryxk
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Are you sure the first derivative of t/e^-t is -(1/e^-t) ?  I get (1+t)e^t

bcnubynby
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t e^t, in one of the laplace transform video, u said that 1/e^infinity much faster to become 0 than the t when t approach to -infinity, so the limit of this is 0

khaileng
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At 5:58, dont we have to use quotient rule?

Bearfair
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Sir can u plzzz say the name of the rule which u used in the last step??

demogorgon
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Sorry, I made a mistake and now understand what was done.  I didn't do the derivative of the proper

bcnubynby