Examples of T1 System | PCM-TDM system | Time Division Multiplexing TDM | Digital Communication

Examples of Time Division Multiplexing TDM are explained by the following outlines:

1. Time Division Multiplexing TDM, TDM/PAM
2. Basics of Time Division Multiplexing TDM
3. T1 Carrier System
4. Examples on Time Division Multiplexing TDM
5. Examples on T1 Carrier System

Chapter-wise detailed Syllabus of the Digital Communication Course is as follows:

Block Diagram of Digital communication system, Advantages, and disadvantages of digital communication system, Scrambling, Regenerative Repeater, Eye Diagram, Attention of signal, Bit rate and Baud rate.

Amplitude Shift Keying ASK, Frequency Shift Keying FSK, Phase Shift Keying PSK, Differential Phase Shift keying DPSK, Quadrature Phase Shift Keying QPSK, Binary Phase Shift Keying BPSK, M array Frequency Shift Keying MFSK, Quadrature Amplitude Modulation QAM, Comparison of QAM and PSK.

Sampling, Aliasing, Nyquist rate, Types of sampling, Performance comparison of sampling, PWM - Pulse width modulation, PPM - Pulse Position modulation, Performance comparison of PAM, PWM and PPM, Quantization and its parameters, SNR of Quantization, Uniform Quantization, Pulse Code Modulation PCM, Nonuniform Quantization, Companding basics, A law and Mu law for Nonuniform quantization, Differential Pulse Code Modulation DPCM, Delta Modulation DM, Adaptive Delta Modulation ADM.

Examples on TDM, Examples on T1 carrier system.

Basic of Line Coding Techniques, Pulse shaping techniques, NRZ, RZ & Manchester coding, PSD of NRZ unipolar line coding scheme, PSD of NRZ polar line coding scheme, PSD of NRZ bipolar line coding scheme, PSD of Manchester polar line coding scheme, Comparison of Unipolar, Polar, Bipolar and Manchester Line coding scheme.

Basics of Information, Basics of Entropy, Shannon Fano Encoding, Huffman Coding, Lempel Ziv Coding, Shannon Hartley theorem, basics of probability, Random variables, Cumulative distribution function CDF, Probability Density function PDF.

Block Codes, Hamming Codes, Linear Block Codes, Cyclic Codes, Convolutional Codes, Code Trellis, Viterbi Algorithm, Block Codes for single parity checks, Block Codes for product codes, Block Codes for Repetition codes, Cyclic codes for a systematic codeword, Cyclic codes for nonsystematic codeword.

Basics of Spread Spectrum Modulation, Frequency Hoping Spread Spectrum FHSS, Direct Sequence Spread Spectrum DSSS.

Engineering Funda channel is all about Engineering, Technology, and Science. This video is a part of Digital communication.

#TimeDivisionMultiplexing #TDM #DigitalCommunication @EngineeringFunda

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[bhai-bmkj]

The best channel for the last-day preparation

[KristianH]

You & this video are the reason why I still have my job. Thank you 😂🤓

[bikashranjansahoo]

sir i am following your digital communication playlist, which is proving very helpful.The way you are delivering the lectures is awesome . I simply wanted to ask what all topics are you going to cover under this playlist?

[yashvardhansingh]

Well done sir. Good explanation, however E1 is relevant in our case. Had to convert ur teaching to corresponding E1 standard. Thanks anyways.

[shubhammodanwal]

Thank you sir ....it will be very helpful for me...

[nikhilKumar-uibs]

Sir why did you take two different formula for Rb and why we didn't use 1/Rb for bit duration.

[anishsinghrajput]

Sir voice sig is band pass signal ..so how we can find fs like this

[vrj-uute]

Sir shudnt the frame duration be called sample duration...duration of one sample of one channel only?

[anirudhkashyap]

What is the difference between Bit rate and Transmission rate?

[shuvo]

In example 1 what is the difference between bit rate and transmission rate?

[mushfiqrana]

Here Why synchronous bit is not counted to find bit duration?
Example 6.10
We have four sources, each creating 250 characters per second. If the interleaved unit is a character
and 1 synchronizing bit is added to each frame, find (a) the data rate of each source, (b) the duration
of each character in each source, (c) the frame rate, (d) the duration of each frame, (e) the number of
bits in each frame, and (f) the data rate of the link.
Solution
We can answer the questions as follows:
a. The data rate of each source is 250 x 8 = 2000 bps = 2 kbps.
b. Each source sends 250 characters per second; therefore, the duration of a character is 1/250 s,
or4 ms.
c. Each frame has one character from each source, which means the link needs to send
250 frames per second to keep the transmission rate of each source.
d. The duration of each frame is 11250 s, or 4 ms. Note that the duration of each frame is the
same as the duration of each character coming from each source.
e. Each frame carries 4 characters and I extra synchronizing bit. This means that each frame is
4 x 8 + 1 =33 bits.