#13||Group of prime order is Cyclic ||Maths for Graduates

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Couple of notes..
1. How can one just assume that there exists an element "a" which has a order n?
2. Moreover, how can there be a subgroup H other than G and e if order of G is prime?
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Combining 1 and 2, it's like just assuming that G is cyclic (with a different name H) containing a generator "a" and then just showing the same thing again. My point being that it was never shown that there will absolutely always be an element "a" within G such that a^n=e. You show that and you have your proof. Merely assuming it is not the proof.
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Edit: Ignore coz there's a proof that in a finite group, all elements have an order. So your proof is correct but it needs to mention this necessity.

kishanprakash