Advance Illustrations - Distance Travelled in 2D Motion | Kinematics #36 for JEE Advanced

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What differentiates JEE Advanced from JEE Mains is multi concept questions so it is very important for JEE advanced aspirants to practice various illustrations.
This advance illustrations series is an excellent run through types of questions asked in JEE Advanced.
In this video Ashish Arora Sir has taken up a case of Topic.

Watch Advanced Illustrations Kinematics videos on various concepts:

#jeeadvance #jeephysics #pgAdvIllustrations #pg4jeeadv #kinematics #rectilinearmotion #projectilemotion
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Sir error analysis, experimental skill ka bhi vidio bana dijiye
Please sir

fsetResearch
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if its for displacement we do displacement = root ( x^2 + y^2 ), right?

and that will come out be a SHM, am I correct ?

kuldeep
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Sir accelration of particle is not zero then how can you use S=UT. please clarify

savant
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How to find distance if velocity were a function of time

thehealthfreak
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Sir if speed comes out to be a function of time, then also distance is equal to v.t?

reemabansal
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Sir cant we find the distance travelled by applying [underroot (dy/dx)^2+1]dx ehich give answer wacoswt underroot(tanwt+1)

arunteltia