Closure of Relations – Part 2

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Discrete Mathematics: Closure of Relations – Part 2
Topics discussed:
1) The definition of symmetric closure.
2) A solved problem based on symmetric closure.
3) The definition of transitive closure.
4) A solved problem based on transitive closure.

Music:
Axol x Alex Skrindo - You [NCS Release]

#DiscreteMathematicsByNeso #DiscreteMaths #Relations #SymmetricClosure #TransitiveClosure
  1. Neso Academy
  2. symmetric closure
  3. transitive closure
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  5. definition of transitive closure
  6. symmetric closure definition
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Комментарии
Автор

Sir, How many more videos are yet to come?

sejaljain
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sir please describe these methods by mathematical representation

HimanshuYadav-dntb
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Okay lets consider
A = {1, 2, 3, 4}
R = {(1, 2), (2, 3), (3, 4)}
Now for transitive closure we add an order pair (1, 3)
So R* = {(1, 2), (2, 3), (1, 3), (3, 4)}
But now this transitive closure is not transitive.... Should i add (1, 4)?

_zerox_X
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this playlist is running from 2 years and yet not completed the full syllabus

pujaupadhyay
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today any video didn't uploaded 😕🤔 . why sir?

monicabattacharya
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neso please start software engineering course

priyadharshini
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Isn't that transitive closure answer should be {1, 1}, {1, 2}, {2, 3}, {3, 1}?

이은규-uo