Can you Solve this Prisoner Riddle?

Can you solve this popular Prisoner Escape Riddle?
Write down in the comments if you were able to solve this mystery riddle!

In todays riddle, a mysterious species of humans has taken you as a prisoner and you need to find the solution to gain back your freedom.
The riddle is based on the popular "100 prisoners and a light bulb" puzzle, which is a difficult and highly complex riddle.

On this Channel i upload a lot lot of riddles and brain teasers. About lying people, escaping a prison or anything where you have to use your brain.
Enjoy! :)

[javiersds]

0:25 I wasn't expecting a Harrison Ford cameo.

[iskoah]

You guys make it so complicated! Everyone leaves one shoe in the room. When there are 10, that person can tell the guard! (If you don't accept this answer, you'll have to create more rules within the riddle)

[vinnyreed]

The ruler of the kidnappers always gives mercy on you and let’s you make strategies

[alessandrobuzzi]

another solution is (it will take much longer time) divide the day in blocks of 10 days. Light can be switched on only if anybody enters the room more the once. If at the 10th day the prisoner enters the room for the first time in the last 10 days and the light is off, he can proclaim, otherwise he switch it off and start again with another row of 10 days.

[tuerda]

Number prisoners 1-10. Divide the day number by 10 and take the remainder. The light being on on day N is used to indicate that you know prisoners 1-N have already been in the room. So, on day 1 if you are prisoner 1, turn the light on. Otherwise leave it off. If you arrive on day 2 and you see it on then you know prisoner 1 has been in the room (so if you show up on day 41, for instance, you can turn on the light because you know prisoner 1 was already there). If you are prisoner 2, leave the light on, otherwise turn it off. On day 3 if the light is on you know both prisoners 1 and 2 have been there, (so if you show up on days 31 or 52, you can turn it on). If you are prisoner 3, you can leave the light on, otherwise turn it off, etc. Whenever prisoner 10 shows up on a day that is a multiple of 10, if the light is on then he can immediately conclude that everyone else has been in the room at least once and announce it.

NOTE: I now watched the solution in the video. It is a lot faster than mine (which is VERY SLOW), but both work.

[michaelsteinberg]

Okay based on the fact that there is no time limit on how long you can be in the prison, just have each prisoner turn on the light when they are in there for the first time and decline to do so every other time. Wait until you count 10 "ON" Days.

[rajivpandey]

What if the person who switches the bulb off is never brought to the hall again. And all the prisoners play this game their whole life and die some day.

[Triggerhawk]

Took me a good 30-60 minutes of thinking at least! Nice one

[vale-lyub]

my solution is that the first person who enters the room is the only one who turns the light on and everyone else turns the light off once. So the first person has to count how many times he turned the light on.

[wonderworld]

I don't understand .... Might I'll have to watch 6-7 times more

[LambTheGod]

Easier solution, before entering the room you make yourself bleed someway(biting the skin/over biting a fingernail). When you enter, wipe a streak of blood on the wall. Once 10 streaks of blood are dried on the wall any prisoner can state we all have entered.

[debbieriley]

I love your channel it helps me progress my mind

[calebbritannia]

It's nice to know if I get captured by natives I will be fine

[debmar]

I'm too busy loving the speaker's accent to focus on the riddle.

[rkvkanyan]

Hi best channel ever keep up the good work

[upsyndrome]

I found a different answer, this being: Before the final day, each prisoner will come to the conclusion of only switching the light switch once. Ex: Prisoner 1 has entered the room twice, he will only switch the light switch the first time, and the second time refuse to do anything with it. The result of this is that the last person (whom must make a choice if every prisoner had been in the room or not) can judge his answer on if the light is on or off. If the light is on, it means that not every prisoner has been in the cell, however if the light is turned off, it means that every prisoner has been to the cell.

Extension or answer to possible errors with this conclusion:

One may say: what is there are only two people who get put into the room, meaning the order will be: 1 2 1 2 1 2 1 2 1 2. The light bulb started off, which means that number 1 will turn it on. Number 2 however will then off again. This will go on until you come to this stage: 1 2 1 2 - The last 2 or prisoner 2 will notice that

NEVER MIND

[shiladityamajumdar]

What if the turns are alternated between only a few prisoners and the main guy enters the room 9 times before a few others have gone in?

[xdxwills]

I have another solution, next to the light switch each prisoner will leave a small scratch in the wall for only the first time they enter the room with the light. Once a prisoner sees 10 scratches on the wall (including his) he will know everyone visited the room.

[donwald]

Holy crap I actually got this one by myself!

[strez_]

Saw this before hahaha.Still rather confusing though.