Physics 70 Principle of Least Action (6 of 27) Principle of Least Action: Easy Ex 2

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We will find the energy needed s=? for the least action of a particle (m=1kg) dropped with an initial velocity of zero (v0=9.8m/s) from a height of height=h=4.9m and reaches the ground in time=t=1s. Example 2

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Комментарии
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The action has the same units/fundamental dimensions as Planck's constant: 6.62607015*10^(-34) Joule-seconds.
Coincidence?

theultimatereductionist
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What about that g in the secund integral i think you forgot to deleted since you pulled out! Or im i wrong. Thank you for the effort. Ur videos helped me alot 5 years ago!

augustisalman
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thank you so much i can finally pass this test im taking tomorrow and pass physics 9th grade year:)

juangonzalez