WARRIOR 2025: ELECTRICITY in 1 Shot: FULL CHAPTER (Theory + PYQs) | Class 10th Boards

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Get ready to ace your Class 10th Boards with this comprehensive video on Electricity! Covering theory and previous year questions, this video will help you master the topic in one shot.
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📌 𝐏𝐇𝐘𝐒𝐈𝐂𝐒 𝐖𝐀𝐋𝐋𝐀𝐇 𝐅𝐎𝐔𝐍𝐃𝐀𝐓𝐈𝐎𝐍 𝐒𝐎𝐂𝐈𝐀𝐋 𝐌𝐄𝐃𝐈𝐀 -
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📌 𝐏𝐇𝐘𝐒𝐈𝐂𝐒 𝐖𝐀𝐋𝐋𝐀𝐇 𝐒𝐎𝐂𝐈𝐀𝐋 𝐌𝐄𝐃𝐈𝐀 -
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Timestamps:
00:00 - Introduction
05:18 - Today’s quote
05:57 - Topics to be covered
07:36 - Electric charge
11:27 - Quantisation of charge
22:17 - Material on the basis of Conductivity
22:34 - Conductors
23:36 - Insulators
24:38 - Semiconductors
25:20 - Electric current
32:02 - Ammeter
33:48 - Potential difference/Voltage analogy
39:16 - Types of current
41:20 - Summary - potential difference
43:04 - Potential
43:40 - Potential difference/Voltage
51:30 - Voltmeter
55:42 - Symbols for circuit diagram
56:40 - Electric circuit and its types
1:03:45 - Ohm’s law
1:09:54 - Verification of Ohm’s law
1:20:28 - Resistance
1:24:25 - Factors affecting resistance
1:25:45 - Resistance and length
1:26:23 - Resistance and area
1:27:28 - Resistance and temperature
1:28:33 - Rheostat
1:35:08 - Specific resistance/Resistivity
1:40:43 - Resistivity and nature of material
1:52:38 - Resistance in Series
1:55:55 - Resistance in Parallel
2:06:45 - Practice ohm’s law problems
2:27:50 - Heating effect of electric current
2:28:26 - Joule’s law of heating
2:31:55 - Applications- Bulb, fuse & coil
2:41:38 - Electric power
2:48:20 - Commercial unit of energy
3:02:05 - Homework
3:03:08 - Thankyou bachhon
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#electricity #Class10 #PhysicsWallahFoundation #PhysicsWallah #CBSEBoard #fullchapter #oneshot #pyqs #theory
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All Formulas of Electricity:
1) I = Q/t
2) Q = ne
3) V = W/Q
4) V = IR
5) R = Rho x L/A
6)Resistance in Series: Rs = R1 + R2 + R3
7)Resistance in Parallel: 1/Rp = 1/R1 + 1/R2 + 1/R3 (» Reciprocal of R1+R2+R3)
8)H = V × Q
i) H = VIt
ii) H = I²Rt
iii) H = V²t/R
9) P = W/t
i) P = VI
ii) P = I²R
iii) P = V²/R
10) E = P × t

S.I. Units:
Current ( I ) - Ampere
Charge ( Q ) - Coulomb
Time ( t ) - Second
Potential Difference or Voltage ( V ) - Volt
Resistance ( R ) - Ohm Ω
Resistivity ( Rho ) - Ohm meter
Power ( P ) - Watt
Heat = Energy = Work = Joule

Measuring Devices:
Ammeter / Milli Ammeter - for measuring current (always connected in series)
Galvanometer - for measuring small/sensitive currents (we can also get the direction of the current)
Voltmeter - for measuring volts (always connected in parallel)
Ohm Meter - Measures the resistivity

Things to remember:
electron charge = (1.6 x 10⁻¹⁹ C)
1kWh= 3.6 × 10⁶J
1Ampere = 1000mA
1 Kilowaat = 1000W
1 Horse Power = 746W

i hope this list will help you! ❤
ek free ka like dete jana
👇
Edit : OMG.. I was not expecting soo many likes. Thank you all..!!!!🤩

Lakshit_sharma-
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2:26:58 Here's The Complete Solution For This Question
Resistance in series= R1 + R2
=> 6 ohm
Resistance In parallel:-
1/R.eq = 1/R1 + 1/R2
1/R.eq = 1/6+1/3
1/R.eq = 9/18
=> R.eq = 2 ohm
To find 'A' :-
V = IR ( Ohm's law )
10=I × 2
=> I = 5A
Therefore, A= 5A

To Find A1:-
V=IR ( Ohm's law )
10=I×3
=> I= 3.33A
Therefore, A1 = 3.33 A
answer..
Hope this helped ;)

AnshRaj-xcxw
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vote for electricity Numerical Question Practice session

Aditya
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Timestamps 🎉🎉🎉🎉🎉😅
00:00 - Introduction
05:18 - Today’s quote
05:57 - Topics to be covered
07:36 - Electric charge
11:27 - Quantisation of charge
22:17 - Material on the basis of Conductivity
22:34 - Conductors
23:36 - Insulators
24:38 - Semiconductors
25:20 - Electric current
32:02 - Ammeter
33:48 - Potential difference/Voltage analogy
39:16 - Types of current
41:20 - Summary - potential difference
43:04 - Potential
43:40 - Potential difference/Voltage
51:30 - Voltmeter
55:42 - Symbols for circuit diagram
56:40 - Electric circuit and its types
1:03:45 - Ohm’s law
1:09:54 - Verification of Ohm’s law
1:20:28 - Resistance
1:24:25 - Factors affecting resistance
1:25:45 - Resistance and length
1:26:23 - Resistance and area
1:27:28 - Resistance and temperature
1:28:33 - Rheostat
1:35:08 - Specific resistance/Resistivity
1:40:43 - Resistivity and nature of material
1:52:38 - Resistance in Series
1:55:55 - Resistance in Parallel
2:06:45 - Practice ohm’s law problems
2:27:50 - Heating effect of electric current
2:28:26 - Joule’s law of heating
2:31:55 - Applications- Bulb, fuse & coil
2:41:38 - Electric power
2:48:20 - Commercial unit of energy
3:02:05 - Homework
3:03:08 - Thankyou bachhon
☝️☝️📈📈📈👍👍👍😁😁

PreetiSingh-fo
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All formulas of electricity:
1) I = Q/t
2) Q = ne
3) V = W/Q
4) V = IR
5) R = Rho × L/A
6) Resistance in series: Rs = R1 + R2 + R3
7) Resistance in parallel: 1/Rp = 1/R1 + 1/R2 + 1/R3(»Reciprocal of R1+R2+R3
8) H = V × Q
i) H = VIT
ii) H = I²RT
iii) H = V²T/R
9) P = W/t
i) P = VI
ii) P = I²R
iii) P = V²/R
10) E = P × T

S.I units:
1) Current ( I ) - Ampere
2) Charge (Q) - coulomb
3) Time ( t ) - second
4) Potential difference or voltage ( V ) - Volt
5)Resistance ( R ) - Ohm
6) Resistivity ( Rho ) - Ohm meter
Power ( P ) - Watt
Heat = Energy = Work = Joule

Measuring Devices
1) Ammeter / Millii Ammeter - for measuring current (always connected in series)
2) Galvanometer - for measuring small/ sensitive currents ( we can also get the direction of the current)
3) Voltmeter - for measuring volts (always connected in parallel)
4) Ohm meter - measures the resistivity

Things to remember:
electron charge = (1.6 × 10-¹⁹ C)
1Kwh = 3.6 × 10⁶J
1 Ampere = 1000 mA
1 Killowatt = 1000 W
1 Horse power = 746W

i hope this list will help you!❤❤

ravindrasharma
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2:26:46
Homework Question:
We are given that,
V = 10 Volts
R1 = 3 Ohm
R2 = 3 Ohm
R3 = 3 Ohm
To find - i) Total current(A)
ii) Current through R3(A1)
Solution:
Rs = 3+3 Ohm = 6 Ohm
Rt = Rs + R3 (In Parallel)
1/Rt = 1/6 + 1/3 Ohm
1/Rt = (1 + 2)/6 Ohm
1/Rt = 3/6 Ohm
1/Rt = 1/2 Ohm
i.e. Rt = 2 Ohm
Now,
V = IR(t)
I = V/R
I = 10V/2 Ohm
Therefore,
i) I(total) = 5A
For R3,
V = I(1)R(3)
I(1) = V/R3
I(1)= 10V/3 Ohm
Therefore,
ii) I(1) = 3.33..A

im_ved
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Sir please 🥺
Next chapter -Magnetic effects of electric current 🔥🔥🔥🔥🔥🔥🔥

manjusingh
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18 minutes ago
All Formulas of Electricity:
1) I = Q/t
2) Q = ne
3) V = W/Q
4) V = IR
5) R = Rho x L/A
6)Resistance in Series: Rs = R1 + R2 + R3
7)Resistance in Parallel: 1/Rp = 1/R1 + 1/R2 + 1/R3 (» Reciprocal of R1+R2+R3)
8)H = V × Q
i) H = VIt
ii) H = I²Rt
iii) H = V²t/R
9) P = W/t
i) P = VI
ii) P = I²R
iii) P = V²/R
10) E = P × t

S.I. Units:
Current ( I ) - Ampere
Charge ( Q ) - Coulomb
Time ( t ) - Second
Potential Difference or Voltage ( V ) - Volt
Resistance ( R ) - Ohm Ω
Resistivity ( Rho ) - Ohm meter
Power ( P ) - Watt
Heat = Energy = Work = Joule

Measuring Devices:
Ammeter / Milli Ammeter - for measuring current (always connected in series)
Galvanometer - for measuring small/sensitive currents (we can also get the direction of the current)
Voltmeter - for measuring volts (always connected in parallel)
Ohm Meter - Measures the resistivity

Things to remember:
electron charge = (1.6 x 10⁻¹⁹ C)
1kWh= 3.6 × 10⁶J
1Ampere = 1000mA
1 Kilowaat = 1000W
1 Horse Power = 746W

i hope this list will help you! ❤
ek free ka like dete jana
👇

DreamJEE-pp
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Vote for magnetic effect of electric current chapter 👍🏻
👇

irshad_
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"EXAM IS NEAR"
"NOTHING IS CLEAR"
"NO NEED TO FEAR"
"BECAUSE PW IS HERE "
😊😊❤

GROWACUTE
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Answer for Question on 2:26:55,
Firstly, Resistance in Series = R1+R2 = 3 ohm+ 3 ohm => 6 ohm.
Total Resistance = 1/Rt = 1/6 + 1/3 = 1+2/6 = 1/2,
i.e, Rt = 2ohm.
i) For A =
V= I x R
10 = I x 2
10/2 = I. Thus, I = 5A.
therefore A = 5A.

For A1,
V = I x R
10 = I x 3
10/3 or 3.34 A = I
Thus, A1 = 3.34 A.

thank YOU, hope this helps, drop a like 😉

Barnam-jzvd
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Timestamps:
00:00 - Introduction
05:18 - Today’s quote
05:57 - Topics to be covered
07:36 - Electric charge
11:27 - Quantisation of charge
22:17 - Material on the basis of Conductivity
22:34 - Conductors
23:36 - Insulators
24:38 - Semiconductors
25:20 - Electric current
32:02 - Ammeter
33:48 - Potential difference/Voltage analogy
39:16 - Types of current
41:20 - Summary - potential difference
43:04 - Potential
43:40 - Potential difference/Voltage
51:30 - Voltmeter
55:42 - Symbols for circuit diagram
56:40 - Electric circuit and its types
1:03:45 - Ohm’s law
1:09:54 - Verification of Ohm’s law
1:20:28 - Resistance
1:24:25 - Factors affecting resistance
1:25:45 - Resistance and length
1:26:23 - Resistance and area
1:27:28 - Resistance and temperature
1:28:33 - Rheostat
1:35:08 - Specific resistance/Resistivity
1:40:43 - Resistivity and nature of material
1:52:38 - Resistance in Series
1:55:55 - Resistance in Parallel
2:06:45 - Practice ohm’s law problems
2:27:50 - Heating effect of electric current
2:28:26 - Joule’s law of heating
2:31:55 - Applications- Bulb, fuse & coil
2:41:38 - Electric power
2:48:20 - Commercial unit of energy
3:02:05 - Homework
3:03:08 - Thankyou bachhon

ABHIMANYU-ABHI
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Vote for Magnetic effect and electrical chapter🎉🎉

payalsharma
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2:26:48 Answer is - A = 5A & A1 = 3.333A

Swarnkar
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2:26:47 A=5 Ampere
B=10/3~ 3.33 Ampere

ishratshah
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1) I = Q/t
2) Q = ne
3) V = W/Q
4) V = IR
5) R = Rho x L/A
6)Resistance in Series: Rs = R1 + R2 + R3
7) Resistance in Parallel: 1/Rp = 1/R1 + 1/
R2 + 1/R3 (» Reciprocal of R1+R2+R3)

Energy/Heat = VQ

i) H = VIt
ii) H = I ^ 2 * Rt
iii) H = V^2/R×t

9) P = W/t
i) P= VI
ii) P = I^2 * R
iii) P = (V^2) / R

10) E=P×t

S.I. Units:

Current (I)- Ampere
Charge (Q) Coulomb
Time (t)- Second
Potential Difference or Voltage (V) - Volt
Resistance (R) Ohm Ω
Resistivity (Rho) - Ohm meter
Power (P) - Watt
Heat = Energy = Work = Joule

Measuring Devices:

Ammeter / Milli Ammeter for measuring current (always connected in series)
Galvanometer for measuring small/sensitive
currents (we can also get the direction of the current)

Voltmeter for measuring volts (always connected in parallel)

Ohm Meter - Measures the resistivity

Things to remember:

electron charge = (1.6 * 10 ^ - 19 * C)

1kWh = 3.6 * 10 ^ 6 * J

1 Ampere 1000mA

1 Kilowaat = 1000W

1 Horse Power = 746W

AyushChauhan-uwxk
Автор

00:00 - Introduction
05:18 - Today’s quote
05:57 - Topics to be covered
07:36 - Electric charge
11:27 - Quantisation of charge
22:17 - Material on the basis of Conductivity
22:34 - Conductors
23:36 - Insulators
24:38 - Semiconductors
25:20 - Electric current
32:02 - Ammeter
33:48 - Potential difference/Voltage analogy
39:16 - Types of current
41:20 - Summary - potential difference
43:04 - Potential
43:40 - Potential difference/Voltage
51:30 - Voltmeter
55:42 - Symbols for circuit diagram
56:40 - Electric circuit and its types
1:03:45 - Ohm’s law
1:09:54 - Verification of Ohm’s law
1:20:28 - Resistance
1:24:25 - Factors affecting resistance
1:25:45 - Resistance and length
1:26:23 - Resistance and area
1:27:28 - Resistance and temperature
1:28:33 - Rheostat
1:35:08 - Specific resistance/Resistivity
1:40:43 - Resistivity and nature of material
1:52:38 - Resistance in Series
1:55:55 - Resistance in Parallel
2:06:45 - Practice ohm’s law problems
2:27:50 - Heating effect of electric current
2:28:26 - Joule’s law of heating
2:31:55 - Applications- Bulb, fuse & coil
2:41:38 - Electric power
2:48:20 - Commercial unit of energy
3:02:05 - Homework
3:03:08 - Thankyou bachhon

2:52 backchodi

Anish_upadhayay
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1:02:50 Entry of Ritik and Akshay Sir😂
Crazy Bhai😂

JustDivy
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3:03:17 magnetic effect of electric current

Saurabh-v
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Home work question answer:-

In the series circuit:
3+3 ohm= 6ohm

In the parallel circuit:
1/Rt= 1/6+1/3= 1+2/6= 3/6= 1/2
=> Rt=2 ohm

A1= v/r= 10/3= 3.33A
A= v/r = 10/2=5A

being_diya