Find the number of Trailing zeros of a factorial number 823! 2023!

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In this video we find the Find the number of trailing zeros of 823! and 2023!
The product formula for the factorial implies that n! is divisible by all prime numbers that are at most n, and by no larger prime numbers. More precise information about its divisibility is given by Legendre's formula, which gives the exponent of each prime p in the prime factorization of n!

823! has 2044 digits and 203 trailing zeros
The sum of 823! digits is 8181
2023! has 5812 digits and 503 trailing zeros
The sum of 2023! digits is 23868


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For arbitrarily large natural numbers N,

the number of trailing zeros of N!
is floor(N/5) + floor(N/5^2) + floor(N/5^3) + … until the last term is zero

This counts the number of 2x5=10 factor pairs noting there are an abundance of 2s

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70! Ortasındaki rakamı bulabilir misiniz?

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