4.24 Refrigerant 134a enters a horizontal pipe operating at steady state at 40°C, 300 kPa, and a

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4.24 Refrigerant 134a enters a horizontal pipe operating at steady state at 40°C, 300 kPa, and a velocity of 40 m/s. At the exit, the temperature is 50°C and the pressure is 240 kPa. The pipe diameter is 0.04 m. Determine (a) the mass flow rate of the refrigerant, in kg/s, (b) the velocity at the exit, in m/s, and (c) the rate of heat transfer between the pipe and its surroundings, in kW.
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Textbooks:
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Fundamentals of Engineering Thermodynamics 8th Edition (Wiley):
Moran, M. J., et. al., 2014, Fundamentals of Engineering Thermodynamics, 8th ed., Wiley, Hoboken, NJ.
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Engineering Mechanics Statics (Pearson):
Hibbeler, R. C. Engineering Mechanics Statics. Pearson Prentice Hall, Pearson Education, 2016.
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WHAT a relief. I was so lost on my error for that last part. But, as my Calc1 professor said years ago...'True or False: Parentheses are important in math?!' ...ESPECIALLY in old school Ti-83's [shout out to my Adult Student Crew!]

...and still coming up with elementary user errors. Fawking hell. 😂
Thanks

lightlove
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Hi, first of all Thanks for all the videos. They are so sufficient for understanding Thermodynamics. At the end of this video, why didn't you write 10^-6 instead of 10^-3 because we converted from m^2 to km^2?

enessgok
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When I rearranged my energy balance equation as in 9:57 I flipped the signs as you did and got -Q= m((h2-h1)+(V2-V1/2)) and worked out -Q= 6.5kJ or Q= -6.5kJ (heat loss from sysem), is this correct? Also when I calculated using your values I got 6.5kJ not 6.82kJ

ReddZepppelin
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The area for a circle is not (pi)d^2 but rather (pi)r^2

matthewpeters
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I’m having trouble grasping the step here at 1:59 If T1 = 40°C and P1 = 3 bar, why is it a SHV? P1 (or 3 bar) is less than 10.164 bar. Wouldn’t it be a compressed liquid? I’ve been seeing a lot of this: “If T is greater than Tsat, it is a SHV”

miguelalvarez