Roman Numeral Converter - JavaScript Algorithms and Data Structures Projects - Free Code Camp

[sjeasley]

Bruh, the fact that you took all this time to walk us through this.... Man, you the real MVP bro. Straight up.

[JonathanWrightZA]

I'm still wrapping my head around this stuff, but once I got the pattern you were going for by XC, I was able to write the rest of the script. Interestingly, this is exactly the format I was going for while I sat in the sun scribbling on a notepad with pen and paper, but just could not get it right. The "+=" aspect is what I'm still grasping and how to and when to use it.

I need to buy you a beer someday. That is all.

[nishikantbawache]

I didn't come across this tutorial in the first attempt. Looked all over to only find solutions which confused me more.
Thanks a lot for taking it step by step, and building it into an easy to understand tutorial.

[yvanneee]

I deeply understand now the use of += thing by this tutorial. so grateful for this sir

[guyarnav]

what a simple solution to a complex problem, thanks for a great tutorial !

[zken]

Thank you Mr. Ian
function convertToRoman(num) {
let answer = "";
let pairs = {
M: 1000,
CM: 900,
D: 500,
CD: 400,
C: 100,
XC: 90,
L: 50,
XL: 40,
X: 10,
IX: 9,
V: 5,
IV: 4,
I: 1,
}

let keys = Object.keys(pairs);
console.log(keys);
while (num > 0) {
let letter = "I"
for (let i = 0; i < keys.length; i++) {
if (num >= pairs[keys[i]]) {
letter = keys[i];
break;
}
}

answer += letter;
num = num - pairs[letter];

}

return answer;
}

[callmeFernie]

You literally snapped Ian! haha Great job as usual!

[lewiszig]

Great. The videos are still valid. Thanks.

[Dman_Ranks]

I found this as a way easier method if this helps anyone stuck!

function convertToRoman(num) {
let romanNum = {
M: 1000,
CM: 900,
D: 500,
CD: 400,
C: 100,
XC: 90,
L: 50,
XL: 40,
X: 10,
IX: 9,
V: 5,
IV: 4,
I: 1
}
let answer = "";
for (let prop in romanNum) {
while (num >= romanNum[prop]) {
num -= romanNum[prop];
answer += prop;
}
} return answer

}

convertToRoman(36);

[shaileshhd]

This is a good pattern for beginners, we can also use objects to solve, which will reduce codes.

[DannyYang]

I appreciate your videos. I went from BIG to small:

function convertToRoman(num) {
let romanNum = "";
while (num > 0) {
if (num >= 1000) {
romanNum += "M";
num -= 1000
} else if (num >= 900) {
romanNum += "CM"
num -= 900
} else if (num >= 500) {
romanNum += "D"
num -= 500
} else if (num >= 400) {
romanNum += "CD"
num -= 400
} else if (num >= 100) {
romanNum += "C"
num -= 100
} else if (num >= 90) {
romanNum += "XC"
num -= 90
} else if (num >= 50) {
romanNum += "L"
num -= 50
} else if (num >= 40) {
romanNum += "XL"
num -= 40
} else if (num >= 10) {
romanNum += "X"
num -= 10
} else if (num >= 9) {
romanNum += "IX"
num -= 9
} else if (num >= 5) {
romanNum += "V"
num -= 5
} else if (num >= 4) {
romanNum += "IV"
num -= 4
} else if (num >= 1) {
romanNum += "I"
num -= 1
}
}
return romanNum;
}

[isiaqridwanbukola]

Thanks a lot, man.
I was actually using an if statement only, l had to come to check my useful programmer when I noticed my line of code is getting longer and longer. I was writing my codes like this before:
if (num > 14 && num < 19) {
// return "X"+"V"+"I".repeat(num - 15)
// }
// if (num > 18 && num < 21) {
// return "X"+"I".repeat(20 - num)+"X"
// }
// if (num > 20 && num < 24) {
// return "X"+"X"+"I".repeat(num - 20)
you know how tedious and long that could be before it can execute all the tasks, smiles.

[salazar]

Others in their 20s: where did my relationship go wrong?

Me in my 20s: Where did my code go wrong?

[abudavid]

The curriculum of fcc is really difficult especially the algorithms

[carlosvenegas]

awesome, thanks for walking through your thoughts

[cosslogan]

Could you use a switch for these type of problems ? I haven't seen a lot of coverage of switch so far in the lessons. Also Thanks for these videos, very informative.

[staaustin]

I would like to point that if you invert the order you wont need the seconds validations

[JD-hqkn]

For the first time I saw you on top of the screen

[fujisan]

Thank you for making this it was really good

[luisjosebolile]

Thanks ... this was difficult .... i made this

function convertToRoman(num) {
let toRest = num ;
let roman = {I:1, IV:4, V:5, IX:9, X:10, XL: 40, L:50, XC:90, C:100, CD:400, D:500, CM: 900, M:1000};
let romanVal = (Object.values(roman));
let romanKey = (Object.keys(roman));
let count = romanVal.length-1
let romanNum =[]

while(count >= 0){
if(romanVal[count] > toRest){
count--;
} else {

toRest -=romanVal[count]
}
}
return romanNum.join("");
}

convertToRoman(36);