Multinomial theorem SE1: coefficient of x^8 in (1+x^2-x^3)^9

preview_player
Показать описание
Multinomial theorem SE1: coefficient of x^8 in (1+x^2-x^3)^9

Support the channel:
Рекомендации по теме
Комментарии
Автор

Support the channel:
PayPal link: paypal.me/mathsmerizing

Mathsmerizing
Автор

i was finding this for too long, finally got it. thanks sir.

ambujbhaskar
Автор

Thank you sir.. your capability to make students understand is phenomenal..

zubairkabir
Автор

r=p
r=1 Σ(ncr), where p<n, n, p, r are + ve integers.

syedmdabid
Автор

Thank you! Was able to understand this concept with ease thanks to your lucid explaination.

Atman_Shah
Автор

Thank you so much sir😭❤️
Even my coaching institute didn't teach me such tricks...
Really thankful to you

pritydas
Автор

Thank you for this problem
Advance congratulations for multinomial subscribers

masterbss
Автор

Channel deserves billions of subscribers😢❤❤

Divyanandp
Автор

So when we have these two possible combinations, is two different combinations alway enough to find any coefficient?
Because there is still more possible combinations. Does it not matter which two we are choosing?

bkalnoky
Автор

Thanked sir
I understood application of multinomial theorem in just 3 min because of you

monicachauhan
Автор

at last, got the solution to this math..thank you so much, sir! From BANGLADESH

shushmitabarua
Автор

a year back i was able to do them on fingers
now i couldnt recall
thanks

abhinav
Автор

Sir u r great, very clear explanation

tapasdas
Автор

sir thanks a lot you made it so simple, this gives me full confidence to ace jee

samanyukamra
Автор

Thank you so much! I was struggling with it

omegahaifoleet
Автор

I had great confusion for this
But now solved 🙂thx

mohdshahnewaz
Автор

Good to know this type of process, tnq sir

maheshuppu
Автор

Really hats off sir you are tuly amainggg 😍😍 sir, your way is just fabulous your students will definitely like ur teaching why u didn't get a teacher like u before 😞😞

_shashank
Автор

Thanx a lot .
This is the thing I was looking for.

anshulsharma
Автор

Tnq vry much sir
Hope every student find a wonderful teacher like u😊

vadthyaravi