Two blocks A and B of masses mA​ =1kg and mB​=3kg are kept on the table as shown in figure

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Two blocks A and B of masses mA​ =1kg and mB​=3kg are kept on the table as shown in figure
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#two_blocks_a_and_b_of_masses_ma_=_1_kg_and_mb_=_3_kg_are_kept_on_the_table_as_shown_in_figure
#fun_with_physics
#jee_mains_question
#two_blocks_problems_friction
#block_on_block_problems_friction

About This video :-
In this video, Deepak Gupta sir is explaining a question asked in JEE mains exam 2019 from friction.
Two blocks A and B of masses mA = 1 kg and mB = 3 kg are kept on the table as shown in figure. the coefficient of friction between A and B is 0.2 and between B and the surface of the table is also 0.2. The maximum force F that can be applied on B horizontally, so that the block A does not slide over the block B is : [Take g = 10 m/s2]
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About D G Sir:-
Deepak Gupta Sir (D.G Sir) is a renowned faculty of physics. He holds a Master's degree from N.I.T. Jalandhar. He is guiding the students of IIT-JEE and NEET for more than 5 years. Under his guidance, several students have achieved their dreams of going into different IITs, NITs, IISERs, and in, different medical colleges.
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About This Channel:-
Dear students,
As you all know that IIT JEE Mains / Advance & NEET are one of the most prestigious and competitive exams of the country, for which lakhs of the students appear every year. These exams are known to be one of the toughest exams for which the students work very hard. A lot of coaching institutes provide good quality coaching and materials to the students so that their efforts and hard work can be reduced a bit. But as we all know that these coachings charge very big fees and a lot of students are not able to pay these big amounts.
That's why this channel Fun with Physics is created where you will find all the quality material for IIT JEE Mains / Advance & NEET explained by our expert faculty in a very simple manner, which is being taught at any coaching in India. You can ask your doubts in the comment box, which will be solved by our expert team very soon.
JAI HIND!
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Thank u so much sir..btw I am your new suscriber sir😊😊

saurabhkumarrabha
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Sir aapke net force f-8 kaise liya kyonki agar aap dono block ko ek system consider kar rahe ho to un dono ke beech ka friction internal force hoga aur cancel ho jayega to block le jo net force hoga voh sirf f-6 hoga jo ki block aur surface ke beech ka friction hai to isse humara answer 14N aayega. Pls clarify🙏

KrishTaparia
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Sir rotational motion ke vedioes please

Abhishek
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Sir plz aap sare pyq ka solution de dijiye plz sir

jaiswalanjali
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Sir how you calculate newton as N=40 how ❓❓❓

gohul
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Sir please koi telegram group banaiye jispe kuch padhai ki cheeze upload ki ja sake

Ajaysingh_
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Aise videos par dislike kon maar deta hai ji 😐

Ajaysingh_
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If you want to study offline with Deepak sir 🤩🤩
Get admission in RPS school behror
IN F1 SECTION
NOT IN A1
11TH CLASS

sanyamyadav