Binomial Probability Distribution

The video covers the Binomial Probability Distribution with respect to the formula, properties and worked examples.
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[Johnvs_]

Thanks sir, much appreciated from south Africa here.

[florabhandari]

This is really good
Explained in such the simplest way 🙂🙂

[AureliaAbemigisha]

your lessons are just incredible. thank you so much for sharing with us

[keshav]

Thanks a lots for very good explanation 😊

[BlessingChizzy-uvrt]

A very good lesson..thank u for this sir, but i have a question

In question 1c
Is there no way it could be solved direct without solving solving for 0, 1 and 2...

[mdjdbneie]

Hello good day. Why does in example 1 letter C you included Probability of 0? We are talking about of having a head right?

[arifurmollah]

I have a question for you 🙋‍♂, in colleges and universities, which math courses talks about Continuous Probability Distribution? Which courses talks about this? Which courses? The reason why I wanted to know which courses talks about Continuous Probability Distributions in colleges and universities because I don't know which courses talks about that? Please give me an answer to the question of which courses talks about Continuous Probability Distribution. Please answer my question.

[saraasare]

Sir please how did you get the probability of success as p and q as a failure from the given question

[maryorimogunje]

This is well explained 🥰🥰
Thank you so much!

[godfrist]

In example 1 how did you got the 32 and 64?

[Lightedpathwithmona]

Thank you so much sir.
This helped me alot

[tregathymk]

Thank you for this wonderful tutorial, well explained 😍

[chisdavidic]

In the example 2 sir how did you get the success(p) and failure (q).

[EdwardNamaheya-ldcv]

On atmost question.. it is possible to use combination of 2 itself and only? Excluding 0?

[cephasagboada]

Please example 1 how did you get the probability to be 1\2

[rosesmith]

Pls how did you get 1/2 in the first example

[munyaradzisibanda]

Thanks very much but I have a lot of questions regarding part b of the second example. If I use Pr(x=0) + Pr(x=1) + Pr(x=2) + Pr(x=3) + Pr(x=4), I get an answer which is greater than 1. This arises from the fact that Pr(x=4)=10/9 which is impossible in probability. If I try your method, I still wonder why you did not subtract Pr(x=6). Otherwise the video was very helpful.

[GideonKips-bk]

What do you mean by 6c4 is 15 I'm not getting it clearly

[ayomidejimmy]

How did you get 1/4 and 3/4 in the third question

[emermbiemer]

the example 2 / b id didn't understand very well why you didnt inclidees even the probabibilty p(x=6) when calculating p(x>, =4 )?