Z-Transform of Basic Signal Problem Example 2

preview_player
Показать описание
Z-Transform of Basic Signal Problem Example 2
Lecture By: Ms. Gowthami Swarna, Tutorials Point India Private Limited
Рекомендации по теме
Комментарии
Автор

To Get Certification, Click Here: bit.ly/3oCIvLA
Use coupon "YOUTUBE12" to get ‘’FLAT 12%’’ OFF at Checkout.

TutorialsPoint_
Автор

For a folded signal a shift of - 1 will be in left.. So the limit will be - 1 to - infinity.. Not 1 to - inifinity

fathimaafreen
Автор

U explained very well, but first and foremost, z transform is incomplete without ROC and limits should be from (-infinity) to (-1)

almostabouteverything
Автор

Mam limit is from -infinity to -1 in this region value of unit step is 1 .

invisibleguy
Автор

U r repeating sme mistke in evry problm, aise kse kam chlega

Also without telling the ROC

akankshasharma
Автор

mam, kindly make it has -infinty to-1.

prajitvishnukarthik
Автор

u(-n-1) represented in wrong way, and this error is compensated further by not changing -1 to 1 when changing the limits !!!

prathameshkulkarni
Автор

Mam you teach well but so many minor mistakes makes your video a bit confusing 🤔🤔🤔🤔

mridul_ojha
Автор

it should be z/z+2... why z/z-2? for 2^n u(-n-1) the 2 does not have a negative infront.

Sometimesitssimplymeh
Автор

how -infinity to 1 become 1 to infinity after reversing. it should 1 to -infinity.

sumanmondal_
Автор

Plz correct shifting of signal.. galti kar ke answer kaise laya

sudeepKumariit
Автор

limits are wrong in both the videos mam

comedyspot
Автор

you write wrong graph of x(-n-1). & wrong limit . its to be -infinity to -1.

arafatjaman
Автор

the limit is correct guys stop confusing people !!!

fasihussaini
Автор

Hello sir/madam I got some question paper so will u solve them please they are from K.U University so plz give me ur mail I'd I will upload u

aruntejaramatenki